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2 years ago

How many Joules in 41.87 kcal?

Physics

2 answers:

maxonik [38]2 years ago

7 0

The answer is 175184.08 joules

gladu [14]2 years ago

4 0

The answer is 175184.08 joules

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A ball is tossed in the air and released. It moves up, reverses direction, falls back down again, and is caught at the same heig

PolarNik [594]

Answer:

The potential energy has a maximum when the ball is a time that is half of the time for total travel

Explanation:

Generally potential energy is a the varies directly with the height according to this formula

$PE =mgh$

and the ball attains a maximum height when the time is equal to half of the total time taken to travel

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2 years ago

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What property of light waves does the michelson-morley interferometer directly demonstrate?

yan [13]

The wave nature of light, due to the experiment having bright and dark bands corresponding to places where you have constructive and destructive interference.

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2 years ago

A 4 kW vacuum cleaner is powered by an electric motor whose efficiency is 90%. (Note that the electric motor delivers 4 W of net

RoseWind [281]

Answer: $3.6\ kW$

Explanation:

Given

Power Supplied $[tex]P_{input}=4\ kW$ [/tex]

Efficiency of the motor $\neta =90\%$

and $\neta =\dfrac{\text{Power output}}{\text{Power input}}$

$\Rightarrow 0.9=\dfrac{P_{out}}{4}$

$\Rightarrow P=0.9\times 4$

$\Rightarrow P=3.6\ kW$

So, vacuum cleaner delivers a power of $3.6\ kW$

3 0

2 years ago

Indique onde em quantos metros o rapaz chegará com as seguintes condições: S0 = 0 a) v = 3 m/s e t = 2 s b) v = 2 m/s e t = 3,5

Naily [24]

Answer:

I will answer in English.

Here we will use the relation

Velocity*time = distance

So:

a) velocity = 3m/s

time = 2s

Distance = 3m/s*2s = 6m

b) velocity = 2m/s

time = 3.5s

Distance = 2m/s*3.5s = 7m

c) velocity = 10m/s

time = 0.5s

Distance = 10m/s*0.5s = 5m

d) velocity = 4m/s

time = 2.5s

Distance = 4m/s*2.5s = 9m

e) velocity = 1.5m/s

time = 5s

Distance = 1.5m/s*5s = 7.5m

8 0

2 years ago

If the mass is displaced 0.270 m from equilibrium and released, what is its speed when it is 0.130 m from equilibrium?

puteri [66]

Answer:

The speed is 1.52 m.

Explanation:

Given that,

Displacement =0.270 m

Distance = 0.130 m

Suppose a 0.321-kg mass is attached to a spring with a force constant of 13.3 N/m.

We need to calculate the angular velocity

Using formula of angular velocity

$\omega=\sqrt{\dfrac{k}{m}}$

Put the value into the formula

$\omega=\sqrt{\dfrac{13.3}{0.321}}$

$\omega=6.43\ rad/s$

We need to calculate the velocity

Using formula of velocity

$v=\omega\sqrt{A^2-x^2}$

Put the value into the formula

$v=6.43\times\sqrt{0.270^2-0.130^2}$

$v=1.52\ m/s$

Hence, The speed is 1.52 m.

6 0

2 years ago