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Sonbull [250]
3 years ago
5

1. Consider the point exactly halfway between the two wires. Can you adjust the current so that, with current passing through ea

ch of the wires, the net field is zero here? 2. Note the distance between the field lines from one of the wires. Are they equally space? Explain. 3. With currents of different magnitudes passing through the two wires, how do the forces on the two wires compare? What is the reason for this?

Physics
1 answer:
chubhunter [2.5K]3 years ago
8 0

Answer:

hello your question is incomplete attached below is missing part of the question

answer:

1 )  Magnetic field due to long current carrying wire : B = \frac{U_{0} I}{2\pi d}

Therefore the net magnetic field due the both wires ; B = B_{1} + B_{2} . when we adjust the current I_{1} = I_{2} then the Netfield (B ) = zero

2) The distance between the field lines are not equally spaced and this is because the separation between field lines increases with the increase in the distance between the wires

3) Increase in current through the wire will lead to increase in force and this can be explained via this equation

F = \frac{U_{0}I_{1}I_{2}   }{2\pi d }

Explanation:

1 )  Magnetic field due to long current carrying wire : B = \frac{U_{0} I}{2\pi d}

Therefore the net magnetic field due the both wires ; B = B_{1} + B_{2} . when we adjust the current I_{1} = I_{2} then the Netfield (B ) = zero

2) The distance between the field lines are not equally spaced and this is because the separation between field lines increases with the increase in the distance between the wires

3) Increase in current through the wire will lead to increase in force and this can be explained via this equation

F = \frac{U_{0}I_{1}I_{2}   }{2\pi d }

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The term "moment of inertia" refers to a physical quantity that quantifies a body's resistance to having its speed of rotation along an axis changed by the application of a torque (turning force). The axis might be internal or exterior, fixed or not.

A) The moment of inertia about an axis passing through the point where the two segments meet is $I_A=\frac{1}{12} M L^2$given that the rod is bent at the center and distance from all the points to the axis remains the same, the moment of inertia about the center will remain the same.

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First step: determine the distance between the ends ( d )

After applying Pythagoras theorem$\mathrm{d}=\frac{\sqrt{2}}{2} L$

Next step : determine distance between the two axis $(\mathrm{x})$

After applying Pythagoras theorem

\mathrm{x}=\frac{\sqrt{2}}{4} L$$

Final step : Calculate the value of $\mathrm{I}_{\mathrm{x}}$

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$$\begin{aligned}& =\frac{1}{12} M L^2+\frac{1}{4} M L^2 \\& \therefore \quad I x=\frac{1}{3} M L^2 \\&\end{aligned}$$

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To learn more about moment of inertia visit:brainly.com/question/15246709

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