The average power is 
Explanation:
First of all, we calculate the work done to accelerate the car; according to the work-energy theorem, the work done is equal to the change in kinetic energy of the car:
where
:
is the final kinetic energy of the car, with
m = 2000 kg is the mass of the car
v = 60 m/s is the final speed of the car
is the initial kinetic energy of the car, with
u = 30 m/s is initial speed of the car
Soolving:
Now we can find the power required for the acceleration, which is given by

where
t = 9 s is the time elapsed
Solving:

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Answer:
4.3 * 10^28 kg
Explanation:
Given:
Period, T = 84s
Radius of satellite orbit, r = 8*10^6
Using the relation :
M = 4π²r³ / GT²
Where G = Gravitational constant, 6.67 * 10^-11
M = 4*π^2*(8*10^6)^3 / 6.67 * 10^-11 * 84^2
M = (20218.191872 * 10^18) / 47063.52 * 10^-11
M = 0.4295937 * 10^18 - (-11)
M = 0.4295937 * 10^29
M = 4.295937 * 10^28 kg
M = 4.3 * 10^28 kg
Mass of planet Nutron = 4.3 * 10^28 kg
Answer:
6 month interval
Explanation:
The distance to a nearby star in theory is more simple than
one might think! First we must learn about the parallax effect. This is the mechanism our eyes use to perceive things at a distance! When we look at the star from the earth we see it at different angles throughout the earth's movement around the sun similar to how we see when we cover on eye at a time. Modern telescopes and technology can help calculate the angle of the star to the earth with just two measurements (attached photo!) Since we know the distance of the earth from the sun we can use a simple trigonometric function to calculate the distance to the star. The two measurements needed to calculate the angle of the star to the earth caused by parallax (in short angle θ) are shown in the second attached photo.
So using a simple trigonometric function
we can solve for d which is the distance of the earth to the star:

In the first attached photo a picture where r is the distance to the star and the base of the triangle is the diameter of the earth.
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