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Anit [1.1K]
3 years ago
6

Determine the force per meter on a lightning bolt at the equator that carries 20 000 A and is perpendicular to the Earth’s magne

tic field, 3x10-5 T. What is the direction of the force if the current is straight up and the Earth’s field direction is due north which is parallel to the ground.
Physics
2 answers:
irga5000 [103]3 years ago
8 0

Answer:

667.6 × 10⁶ Nm

Explanation:

To determine the force, let:

The force be  = 20 000 A

The magnetic field = 3 × 10⁻⁵

Thus, the force will be = \frac{20000}{3*10^{5} } \\ = 666.67 * 10^{6} N m

Thus, the direction will be parallel to the equator

Sladkaya [172]3 years ago
6 0
To determine the force per meter of a light bolt at the equator that carries 20 000 A and is perpendicular to the Earth's magnetic field with a magnitude of 3x10-5 T, we do this:
20000 / 3x10-5 = 666.67x10^6 N/m

The direction of the force would be to the left parallel to the equator.
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