Question

Determine the force per meter on a lightning bolt at the equator that carries 20 000 A and is perpendicular to the Earth’s magnetic field, 3x10-5 T. What is the direction of the force if the current is straight up and the Earth’s field direction is due north which is parallel to the ground.

Answer 1

Answer:

667.6 × 10⁶ Nm

Explanation:

To determine the force, let:

The force be  = 20 000 A

The magnetic field = 3 × 10⁻⁵

Thus, the force will be = $\frac{20000}{3*10^{5} } \\ = 666.67 * 10^{6} N m$

Thus, the direction will be parallel to the equator

Answer 2

To determine the force per meter of a light bolt at the equator that carries 20 000 A and is perpendicular to the Earth's magnetic field with a magnitude of 3x10-5 T, we do this:
20000 / 3x10-5 = 666.67x10^6 N/m

The direction of the force would be to the left parallel to the equator.