Question

A line with the slope of -3 passes through (-8, p) and (2, 3p). Find the value of p

Answer 1

Answer:

To find the Slope: Slope Formula: m = y2 −y1 x2 −x1. Given points: P (6,2) and S(3,1) will be our (x1,y1) and (x2,y2) respectively. Hence x1 = 6,y1 = 2,x2 = 3,y2 = 1. Slope(m) = 1 −2 3 −6. ⇒ −1 −3 = 1 3.

Step-by-step explanation:

Answer 2

Answer:

p = -15

Step-by-step explanation:

$-3=\frac{3p-p}{2-(-8)} =\frac{2p}{10}$

$\frac{2p}{10} =-3$

$2p=-3(10)$

$p=\frac{-30}{2}$

$p=-15$

$m=\frac{-45-(-15)}{2-(-8)} =\frac{-45+15}{2+8} =\frac{-30}{10} =-3$

I hope this help you