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ivann1987 [24]
2 years ago
15

A nugget of gold is placed in a graduated cylinder that contains 80 mL of water. The water level rises to 225 mL after the nugge

t is added to the cylinder. What is the volume of the gold nugget?
Chemistry
1 answer:
Marina CMI [18]2 years ago
8 0

Answer:

<h2>145 mL</h2>

Explanation:

The volume of the nugget can be found by using the formula

volume of object = final volume of water - initial volume of water

From the question

final volume of water = 225 mL

initial volume = 80 mL

We have

volume = 225 - 80 = 145 mL

We have the final answer as

<h3>145 mL</h3>

Hope this helps you

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Why does group 18 in the periodic table not form ions?
alukav5142 [94]
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Now.. lets take some time to think about why elements want to form ions: 

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4 0
2 years ago
Choose the most electronegative atom from the following: K, Mg, As, CI
lyudmila [28]

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8 0
2 years ago
what is the pH of a solution that results when 0.010mol HNO3 is added to 500.ml of a solution that is 0.10M in aqueous ammonia a
WARRIOR [948]

Answer : The  

pH of a solution is, 8.56

Explanation : Given,

K_b=1.8\times 10^{-5}

Concentration of ammonia (base) = 0.10 M

Concentration of ammonium nitrate (salt) = 0.55 M

First we have to calculate the value of pK_b.

The expression used for the calculation of pK_b is,

pK_b=-\log (K_b)

Now put the value of K_b in this expression, we get:

pK_b=-\log (1.8\times 10^{-5})

pK_b=5-\log (1.8)

pK_b=4.7

Now we have to calculate the pOH of buffer.

Using Henderson Hesselbach equation :

pOH=pK_b+\log \frac{[Salt]}{[Base]}

Now put all the given values in this expression, we get:

pOH=4.7+\log (\frac{0.55}{0.10})

pOH=5.44

The pOH of buffer is 5.44

Now we have to calculate the pH of a solution.

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Thus, the pH of a solution is, 8.56

8 0
2 years ago
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