The [H₃0⁺] of the solution : 1.778 x 10⁻¹² M
<h3>Further explanation </h3>
pH is the degree of acidity of a solution that depends on the concentration of H⁺ ions. The greater the value the more acidic the solution and the smaller the pH.
pH = - log [H⁺]
So that the two quantities between pH and [H⁺] are inversely proportional because they are associated with negative values.
A solution whose value is different by n has a difference in the concentration of H⁺ ion of 10ⁿ.
pH of solution = 11.75
the [H₃0⁺] of the solution :
![\tt pH=-log[H_3O^+]\\\\11.75=-log[H_3O^+]\\\\(H_3O^+]=10^{-11.75}=1.778\times 10^{-12}](https://tex.z-dn.net/?f=%5Ctt%20pH%3D-log%5BH_3O%5E%2B%5D%5C%5C%5C%5C11.75%3D-log%5BH_3O%5E%2B%5D%5C%5C%5C%5C%28H_3O%5E%2B%5D%3D10%5E%7B-11.75%7D%3D1.778%5Ctimes%2010%5E%7B-12%7D)
Answer:
2.5 moles of KOOH are produced.
Explanation:
1)Given data:
Number of moles of KOOH produced = ?
Number of moles of LiClO = 5 mol
Solution:
Chemical equation:
2LiClO + KHSO₄ → Li₂SO₄ + Cl₂ + KOOH
now we will compare the moles of KOOH and LiClO.
LiClO : KOOH
2 : 1
5 : 1/2×5 = 2.5
2.5 moles of KOOH are produced.
A group goes vertically and a period goes horizontally.
(a group goes down and a period goes across)