Question

What is the pressure of 0.5 mol of nitrogen gas in a 5 L container at 203 K

Answer 1

Answer:

1.67 atm.

Explanation:

• We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm (P = ??? atm).

V is the volume of the gas in L (V = 5.0 L).

n is the no. of moles of the gas in mol (n = 0.5 mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (T = 203 K).

∴ P = nRT/V = (0.5 mol)(0.0821 L.atm/mol.K)(203 K)/(5.0 L) = 1.67 atm.