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Nataliya [291]
2 years ago
9

What is the difference between a distraction and a reaction

Chemistry
2 answers:
sdas [7]2 years ago
5 0
The difference between a distraction and a reaction is.... A distraction is a thing that prevents someone from giving full attention to something else. A reaction is a action performed or a feeling experienced in response to a situation or an event.
pishuonlain [190]2 years ago
3 0
Distractions draw attention from another thing, and a reaction is what happens because of a happening
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Explain how you would find the mass percent<br> of each element in water.
nydimaria [60]

Answer:

finding the mass percentage oven element in a compound might sound complicated, but the calculation is simple. For example, to determine the mass percentage of hydrogen in water H2O, divide the major mass of hydrogen by the total molar mass of water and then multiply the result by 100

3 0
3 years ago
What is the definition of pendulum
Mama L [17]

Answer:

weight hung from a fixed point so that it can swing freely backward and forward.

5 0
2 years ago
Read 2 more answers
When combing one's hair, the comb becomes positively charged. What happens to the hair being combed?
TEA [102]

Since the comb is positively charged, the hair will stick to the comb.

I think

6 0
3 years ago
How many moles of glucose can be produced
Arturiano [62]

Answer:

moles of glucose

<u>2.3166 moles of glucose</u>

<u></u>

Explanation:

The balance reaction for the formation of glucose is :

6CO_{2}+6H_{2}O\rightarrow C_{6}H_{12}O_{6}+6O_{2}

here , CO2 = carbon dioxide

H2O = water

C6H12O6 = glucose

O2 = Oxygen

According to this equation :

6 mole of CO2 = 6 mole of H2O = 1 mole of C6H12O6 = 6 mole of O2

We are asked to calculate the mole of Glucose from carbon dioxide.

So,

6 mole of CO2  produce = 1 mole of C6H12O6

1 mole of CO2 will produce =

\frac{1}{6} moles of glucose

13.9 moles of CO2 will produce :

\frac{1}{6}\times 13.9

=2.3166 moles of glucose

Note : first , Always calculate for one mole (By dividing)

. After this , multiply the answer with the moles given.

Always write the substance whose amount is asked(glucose) to the right hand side

5 0
3 years ago
What mass of lead (II) chloride is produced when 200.0 mL of a 0.250 M solution of sodium chloride is mixed with 200.0 mL of a 0
kow [346]

Answer:

Option d. 6.95 g

Explanation:

First of all, we state the reaction:

2NaCl + Pb(NO₃)₂ → PbCl₂ +  2NaNO₃

We determine the moles of each reactant, to state the limiting

Firstly we convert volume frm mL to L

0.200 L . 0.250M = 0.05 moles of NaCl

0.200L . 0.250M = 0.05 moles of Pb(NO₃)₂

Acording to stoichiometry we know that relation is 1:2, so the limiting reagent is the NaCl.

For 1 mol of Pb(NO₃)₂ I need 2 moles of NaCl

For 0.05 moles of Pb(NO₃)₂ I would need, the double → 0.1 moles

(We only have, 0.05 moles of NaCl)

Stoichiometry to the formed product is 2:1

From 2 moles of NaCl I produce 1 mol of PbCl₂

From 0.05 moles I would produce, the half → 0.025 moles

Let's convert the moles to mass → 0.025 mol . 278.1 g / 1mol = 6.95 g

8 0
3 years ago
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