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Nataliya [291]
3 years ago
9

What is the difference between a distraction and a reaction

Chemistry
2 answers:
sdas [7]3 years ago
5 0
The difference between a distraction and a reaction is.... A distraction is a thing that prevents someone from giving full attention to something else. A reaction is a action performed or a feeling experienced in response to a situation or an event.
pishuonlain [190]3 years ago
3 0
Distractions draw attention from another thing, and a reaction is what happens because of a happening
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NEED ANSWER ASAP!<br> How many grams are in 1.50 moles of bromine liquid?
padilas [110]

Answer:

119.85 grams Br or 120. grams Br (sig figs)

Explanation:

1.50 moles Br          79.90 g Br

--------------------- x ------------------------ = 119.85 grams Br or 120 grams Br (sig figs)

                                     1 mole

7 0
3 years ago
Which law relates temperature, pressure, volume, and the number of moles of a gas under perfect conditions?
kozerog [31]
Ideal Gas law PV=nRT

P- pressure(atm)
V-volume( liter)
R- gas constant
T- temperature(kelvin)
n - number of moles
6 0
3 years ago
Read 2 more answers
A substance with a pH of 4.0?
IrinaVladis [17]
Tomato juice or acid rain
7 0
3 years ago
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Find the number of molecules in 27 grams of water
Aleks04 [339]

In this question we have given the gram of water and we know that 1 mole of water = 18 gram of water and 27 g of water contain 1.5 g of water 27 / 18 = 1.5 g

As we know that avogandro'S no is equal 6.022*1023

1.5g * 6.022*1023 = 9.0 * 1023 molecules present in each 27 g of water.

I hope you will understand better now if you like then comment below and tell me. Best of luck.

5 0
3 years ago
131i has a half-life of 8.04 days. assuming you start with a 1.53 mg sample of 131i, how many mg will remain after 13.0 days ___
inn [45]
For this problem we can use half-life formula and radioactive decay formula.

Half-life formula,
t1/2 = ln 2 / λ

where, t1/2 is half-life and λ is radioactive decay constant.
t1/2 = 8.04 days

Hence,         
8.04 days    = ln 2 / λ                         
λ   = ln 2 / 8.04 days

Radioactive decay law,
Nt = No e∧(-λt)

where, Nt is amount of compound at t time, No is amount of compound at  t = 0 time, t is time taken to decay and λ is radioactive decay constant.

Nt = ?
No = 1.53 mg
λ   = ln 2 / 8.04 days = 0.693 / 8.04 days
t    = 13.0 days 

By substituting,
Nt = 1.53 mg e∧((-0.693/8.04 days) x 13.0 days))
Nt = 0.4989 mg = 0.0.499 mg

Hence, mass of remaining sample after 13.0 days = 0.499 mg

The answer is "e"

8 0
3 years ago
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