Question

F(x) = -x^2+ 6x -10 write each function in vertex form and give the vertex

Answer 1

Answer:

Vertex form: f(x) = – (x – 3)² – 1  

vertex: (3, -1)

Step-by-step explanation:

Given the quadratic function, f(x) = -x²+ 6x -10:

where a = -1, b = 6, and c = -10

The vertex of a parabola is the point at which the parabola intersects the axis of symmetry. The axis of symmtery occurs at x = h. Therefore, the x-coordinate of the vertex is the same as h.

To find the vertex, (h, k), you need to solve for h by using the formula:  $h = \frac{-b}{2a}$

Plug in the values into the formula:

$h = \frac{-b}{2a}$

$h = \frac{-6}{2(-1)} = 3$

Therefore, h = 3.

Next, to find the k, plug in the value of h into the original equation:

f(x) = -x²+ 6x -10

f(x) = -(3)²+ 6(3) -10

f(x) = -1

Therefore, the value of h = -1.

The vertex = (3, -1).

Now that you have the value for the vertex, you can plug these values into the vertex form:

f(x) = a(x - h)² + k

a =  determines whether the graph opens up or down, and makes the parent function wider or narrower.

• If a is positive, the graph opens up.
• If a is negative, the graph opens down.

h = determines how far left or right the parent function is translated.

k = determines how far up or down the parent function is translated.

Plug in the vertex, (3, -1) into the vertex form:

f(x) = – (x – 3)² – 1  

This parabola is downward-facing, with its vertex, (3, -1) as its maximum point on the graph.