Complete Question
The complete question is shown on the first uploaded image
Answer:
a

b
c
The correct option is D
Step-by-step explanation:
From the question we are told that
The margin of error is 
The largest value is k = 15
The smallest value is u = 7
From the question we are told the confidence level is 95% , hence the level of significance is
=>
Generally from the normal distribution table the critical value of
is
Generally population standard deviation estimate is mathematically represented as

Here the Range is mathematically represented as

=> 
=> 
=> 
=> 
Generally the sample size is mathematically represented as
![n = [\frac{Z_{\frac{\alpha }{2} } * \sigma }{E} ] ^2](https://tex.z-dn.net/?f=n%20%3D%20%5B%5Cfrac%7BZ_%7B%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%7D%20%2A%20%20%5Csigma%20%7D%7BE%7D%20%5D%20%5E2)
=> ![n = [1.96 * 2 }{0.23} ] ^2](https://tex.z-dn.net/?f=n%20%3D%20%5B1.96%20%20%2A%20%202%20%7D%7B0.23%7D%20%5D%20%5E2)
=> 
Generally to obtain a conservatively small sample size the population standard deviation estimate becomes
=> 
=> 
=> 
Generally the conservatively small sample size is mathematically evaluated as
![n = [\frac{Z_{\frac{\alpha }{2} } * \sigma }{E} ] ^2](https://tex.z-dn.net/?f=n%20%3D%20%5B%5Cfrac%7BZ_%7B%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%7D%20%2A%20%20%5Csigma%20%7D%7BE%7D%20%5D%20%5E2)
=> ![n = [1.96 * 1.333 }{0.23} ] ^2](https://tex.z-dn.net/?f=n%20%3D%20%5B1.96%20%20%2A%20%201.333%20%7D%7B0.23%7D%20%5D%20%5E2)
=>
L=7+w
P=(12x+14)=2(6x+7)
l+w= P/2 = 2(6x+7)/2= 6x+7
l+w=6x+7
2l = 6x+7
l = (6x+7)/2
l=7+w
-> w= l-7
= [(6x+7)/2] -7
= (6x+7-14)/2
= (6x-7)/2

so, let's first change the bounds from 1 to 9, so we'll be dropping the indices by 1, in order to do the variable "n".
however, let's use a variable hmmm say "k", where "k" is the value of "n" beginning at 1, thus
k = n - 1.
however, if k = n - 1, then
k + 1 = n. So let's use those fellows then,
Answer:
The width of the vegetable garden is 3 feet.
Step-by-step explanation:
12 ÷ 4 = 3