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marishachu [46]
2 years ago
10

What is the missing reason for the 5th step in the proof below?

Mathematics
2 answers:
Alex777 [14]2 years ago
5 0

Answer:

Rv and EA

Step-by-step explanation:

Because ik

MrRa [10]2 years ago
5 0

Answer: B

Step-by-step explanation:

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Find the slope of a line that passes through the points (2,-1) and (4,7)
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if I did it correctly then it is y= 1/4x-9/4

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5 0
2 years ago
24 divide by blank plus 5 multipled by 3 plus 2 equals 20
sineoko [7]

Answer:

8

Step-by-step explanation:

The answer would be 8 because the question would be

24 ÷ x + 5 × 3 + 2=20  right?

The first thing you would want to do is multiply the 5 and the 3 because of PEMDAS which should give you  24 ÷ x + 15 + 2 = 20.

15 plus 2 is 17 and then you would subtract 17 from 20 which would give you 3. So you know know that 24÷x has to be 3 and 24÷3 is 8 so x=8.

Hope this helped!

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3 years ago
Complete the table and then find the function rule. Remember to put in the y=mx+b form
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1. 81        2. -20      3.  168       4.  -24

Step-by-step explanation:

I hope this is right :)

8 0
2 years ago
Rewrite `10^{32}\ \/ \ 10^{6}\ `using a single exponent.
IrinaVladis [17]

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8 0
3 years ago
[HELP] For j(x) = <img src="https://tex.z-dn.net/?f=5%5Ex%5E-%5E3" id="TexFormula1" title="5^x^-^3" alt="5^x^-^3" align="absmidd
Alina [70]

The difference quotient of the function that has been presented to us will turn out to be 5.

<h3>How can I calculate the quotient of differences?</h3>

In this step, we wish to determine the difference quotient for the function that was supplied.

To begin, keep in mind that the difference quotient may be calculated by:

Lim h->0 \frac{f(x+h)-f(x)}{h}

Now, for the purpose of the function, we need this:

Then we will have:

$$\begin{aligned}&\lim _{h \rightarrow 0} \frac{j(x+h)-j(x)}{h} \\&\lim _{h \rightarrow 0} \frac{5 *(x+h)-3-5 * x+3}{h} \\&\lim _{h \rightarrow 0} \frac{5 x+5 h-3-5 x+3}{h} \\&\lim _{h \rightarrow 0} \frac{5 h}{h}=5\end{aligned}$$

j(x) = 5x - 3

Then the following will be true:

Therefore, 5 is the value of the difference quotient for j(x) is %

Read the following if you are interested in finding out more about difference quotients:

brainly.com/question/15166834

#SPJ1

6 0
11 months ago
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