Ask question

Ask question

All categories

3 years ago

6

PLSSS HELP IF YOU TURLY KNOW THISS

2 answers:

Lelu [443]3 years ago

8 0

Step-by-step explanation:

$\frac{3}{5}$

$= \frac{3 \times 2}{5 \times 2}$

$= \frac{6}{10}$

$=0.6$

$HOPE \: IT \: HELPS \: YA$

pshichka [43]3 years ago

4 0

Answer:

0.6

Step-by-step explanation:

3/5

(3 x 2)/(5 x 2)=6/10=0.6

Hope this helps!

You might be interested in

1. Find the remainder if f(x) = 2x³ + 8x² – 5x + 5 is divided by x – 2.

Hunter-Best [27]

Answer:

The answer to your question is 43

Step-by-step explanation:

2x³ + 8x² - 5x + 5 / x - 2

Process

1.- Use synthetic division

2 8 -5 5 2

4 24 38

2 12 19 43

Quotient 2x² + 12x + 19

Remainder 43

4 0

3 years ago

Write 12.9 + 8 using words.

Anna35 [415]

Twelve point nine plus eight equals twenty point nine (12.9 + 8 = 20.9)
Hope this helped :)

7 0

3 years ago

Learning Task 3

ASHA 777 [7]

Answer:

1. The sides are: 38.5, 39.5, 40.5 and 41.5

2. Presently, Inzo is 15 years old and Miz is 10 years old

3. $Distance = 3682km$

4. Possible pairs are: (12, 14), (16, 18) and (20, 24)

5. $L < 38m$

Step-by-step explanation:

The question has lots of missing details. See the comment section for complete question

Solving (a):

Given

Shape: Quadrilateral

Sides: Consecutive

$Perimeter = 160$

Let one of the sides be x. The other sides will be x + 1, x + 2 and x + 3.

So, the perimeter is:

$Perimeter = x + x + 1 + x + 2 + x + 3$

This gives:

$160 = x + x + 1 + x + 2 + x + 3$

Collect Like Terms

$160 -1-2-3= x+x+x+x$

$154= 4x$

Divide both sides by 4

$38.5 = x$

$x =38.5$

<em>So, the sides are: 38.5, 39.5, 40.5 and 41.5</em>

<em></em>

Solving (b):

Given

Presently: $Inzo = 10 + Miz$

Five years ago: $Miz - 5= \frac{1}{3} * (Inzo-5)$ --- (Missing from the question)

Required: Determine their present ages

Substitute $10 + Miz$ for Inzo in the second equation

$Miz - 5 = \frac{1}{3} * (10 + Miz - 5)$

$Miz - 5 = \frac{1}{3} * (Miz + 5)$

Multiply both sides by 3

$3Miz - 15 = Miz + 5$

Collect Like Terms

$3Miz -Miz = 15 + 5$

$2Miz= 20$

Divide both sides by 2

$Miz = 10$

Substitute 10 for Miz in $Inzo = 10 + Miz$

$Inzo = 10 + 5$

$Inzo = 15$

<em>So presently, Inzo is 15 years old and Miz is 10 years old</em>

Solving (3):

Given

Express Train:

$Speed = 100kph$

$Time = t$

Local Train:

$Speed = 45kph$

$Time = t + 45$

Required: Determine the distance between A and B

Distance is calculated as:

$Distance = Speed * Time$

For the express train:

$Distance = 100 * t$

For the local train

$Distance = 45 * (45 + t)$

Distance between both stations are equal; So,

$100 * t = 45 * (45 + t)$

$100 t = 2025 + 45t$

Collect Like Terms

$100 t -45t= 2025$

$55t= 2025$

Divide by 55

$t = 36.82$

Substitute 36.82 for t in $Distance = 100 * t$

$Distance = 100 * 36.82$

$Distance = 3682km$

Solving (4):

Let the even numbers be: n and n + 2.

Sum greater than 24: $n + n + 2 > 24$

Sum less than 60: $n + n + 2 < 60$

So, we have:

$n + n + 2 > 24$

$2n + 2 > 24$

Collect Like Terms

$2n > 24-2$

$2n > 22$

$n > 11$

$n + n + 2 < 60$

$2n + 2< 60$

Collect Like Terms

$2n < 60-2$

$2n < 58$

Divide by 2

$n$

So, we have:

$n > 11$ and $n < 29$

So, possible pairs are: (12, 14), (16, 18) and (20, 24)

Solving (5):

Given

$Perimeter < 152m$

Required: Find the possible lengths

Let the length be L.

Perimeter is calculated as:

$Perimeter =4 * L$

$Perimeter =4 L$

So, we have:

$4L < 152m$

Divide through by 4

$L < 38m$

Hence, length is less than 38m (e.g. 37m)

5 0

3 years ago

david is 8 years older than stephen and 2 years younger than Graham. if Neil is 7 years younger than Graham, how much older than

ANEK [815]

5 years older...cause if David is 2 years younger than Graham & Neil is 7 years younger than Graham...7-2=5 years :)

6 0

3 years ago

What statement is true?

givi [52]

Answer:

$\frac{18}{32}>\frac{16}{32}$

Step-by-step explanation:

We need to find which statements are true.

Solution to find the same we will solve each statement and will conclude the same.

1. $\frac{14}{21}>\frac{17}{24}$

Now On solving we get;

$\frac{14}{21} = 0.66$

$\frac{17}{24}=0.70$

So we can see that 0.70 > 0.66

Hence The given statement is False.

2. $\frac{18}{32}>\frac{16}{32}$

Now On solving we get;

$\frac{18}{32}=0.5625$

$\frac{16}{32}= 0.5$

So we can see that 0.5625 > 0.5

Hence The given statement is True.

3. $\frac{20}{15}$

Now On solving we get;

$\frac{20}{15} = 1.33$

$\frac{28}{23}=1.2$

So we can see that 1.33 > 1.2

Hence The given statement is False.

4. $\frac{29}{35}$

Now On solving we get;

$\frac{29}{35}= 0.82$

$\frac{20}{30}= 0.66$

So we can see that 0.82 > 0.66

Hence The given statement is False.

7 0

3 years ago