All categories

3 years ago

Need help asap due tmr !!!

Mathematics

2 answers:

mezya [45]3 years ago

6 0

Here! not sure if it's right but i'm pretty confident. boom

kobusy [5.1K]3 years ago

3 0

Answer:

Inequality: 6 ≤ n+15

Solution: -9≤n

You might be interested in

Slope and rate of changes describe the same value true or false

Anit [1.1K]

Answer:

True

Step-by-step explanation:

“Rate of change” means the same as “slope.” If you are asked to find the rate of change, use the slope formula or make a slope triangle.

8 0

3 years ago

If you place a 13-foot ladder against the top of a 12-foot building, how many feet will the bottom of the ladder be from the bot

Degger [83]

13^2=12^2+x^2
25=x^2
5=x

5 0

3 years ago

Read 2 more answers

How many feet are in 154 centimeters

klio [65]

Step-by-step explanation:

154 centimeters =

5.05249344 feet (5 feet ⅝ inch)

4 0

3 years ago

Read 2 more answers

At noon, ship A is 130 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 20 km/h. How fast is

Hitman42 [59]

Answer:

answer = 12.87 km/h

Step-by-step explanation:

Given

Ship A is sailing east at 25 km/h = $\frac{dx}{dt}$

ship B is sailing north at 20 km/h = $\frac{dy}{dt}$

here x and y are the sailing at t = 4 : 00 pm for ship A and B respectively

so we get x = 4 ×25 =100 km/h

y = 4× 20 = 80 km/h

let z is the distance between the ships, we need to find $\frac{dz}{dt}$ at t = 4 hr

At noon, ship A is 130 km west of ship B (12:00 pm)

so equation will be

$z^2 = (130-x)^2 + y^2......................(i)\\put x = 100 and y = 80 \\\\we | | get \\$

$z^2 = 30^2 + 80^2\\z =\sqrt{7300} km/h$

derivative first equation w . r. to t we get

$2z\frac{dz}{dt} =$ $-2(130-x)\frac{dx}{dt}$ $+2y\frac{dy}{dt}$

$\frac{dz}{dt} =\frac{1}{z}[(x -130)\frac{dx}{dt} +y\frac{dy}{dt}]$

$\frac{dz}{dt} = \frac{( -20\times25 + 80\times20)}{\sqrt{7300} }$

$= \frac{1100}{85.44}\\ = 12.87km/h$

8 0

3 years ago

1 4 6 60 7 9 10TIME REMAIN41:42For a snack, Sameer ate a plum with 32 calories and several strawberries with 4 calories each. If

Alex777 [14]

Well, if Sameer's plum was 32 calories, and we know his total snack was 56 calories, all we have to do is:

56-32=24

24 / 4 = 6

Sameer ate one plum (32Kcal) and 6 strawberries (4Kcal each)

8 0

3 years ago