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olganol [36]
3 years ago
5

Compare using >, <, or =. 3 miles_5,000 yards

Mathematics
1 answer:
lina2011 [118]3 years ago
4 0

Answer:

3 miles = 5280 yds

5280 yds > 5,000 yds

in this case 3 miles is greater than 5,000 yards

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Can you solve the equation?
Andreas93 [3]

Answer:

x=3 and 9

Step-by-step explanation:

; x-3=0

x=3 (change side change mark)

and

\frac{2}{3} x - 6 = 0

\frac{2}{3} x = 6

x = 6 \times  \frac{3}{2}

change side change mark.

So, x=9

If u wanna check the answer you can check by substitution x=3 and 9 in equation.

hope it helps you ☺️

3 0
3 years ago
I need help now it’s due soon
zalisa [80]

Answer:

Ordered pairs are ( -3, 0) (0, 3)

Step-by-step explanation:

Now when your graphing, go up 3 spots in the y-axis ( up & down) and plot your point now do the same for your x-axis (( left and right), so go over to the left 3 places, and there now connect the 2 points and your done. Hope that helps!

7 0
2 years ago
Let X be a set of size 20 and A CX be of size 10. (a) How many sets B are there that satisfy A Ç B Ç X? (b) How many sets B are
Svetlanka [38]

Answer:

(a) Number of sets B given that

  • A⊆B⊆C: 2¹⁰.  (That is: A is a subset of B, B is a subset of C. B might be equal to C)
  • A⊂B⊂C: 2¹⁰ - 2.  (That is: A is a proper subset of B, B is a proper subset of C. B≠C)

(b) Number of sets B given that set A and set B are disjoint, and that set B is a subset of set X: 2²⁰ - 2¹⁰.

Step-by-step explanation:

<h3>(a)</h3>

Let x_1, x_2, \cdots, x_{20} denote the 20 elements of set X.

Let x_1, x_2, \cdots, x_{10} denote elements of set X that are also part of set A.

For set A to be a subset of set B, each element in set A must also be present in set B. In other words, set B should also contain x_1, x_2, \cdots, x_{10}.

For set B to be a subset of set C, all elements of set B also need to be in set C. In other words, all the elements of set B should come from x_1, x_2, \cdots, x_{20}.

\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}&  \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{Maybe} & \cdots & \text{Maybe}\end{array}.

For each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus 2^{10} = 1024 possibilities for set B.

In case the question connected set A and B, and set B and C using the symbol ⊂ (proper subset of) instead of ⊆, A ≠ B and B ≠ C. Two possibilities will need to be eliminated: B contains all ten "maybe" elements or B contains none of the ten "maybe" elements. That leaves 2^{10} -2 = 1024 - 2 = 1022 possibilities.

<h3>(b)</h3>

Set A and set B are disjoint if none of the elements in set A are also in set B, and none of the elements in set B are in set A.

Start by considering the case when set A and set B are indeed disjoint.

\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}&  \text{No}&\text{No}&\cdots &\text{No}& \text{Maybe} & \cdots & \text{Maybe}\end{array}.

Set B might be an empty set. Once again, for each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus 2^{10} = 1024 possibilities for a set B that is disjoint with set A.

There are 20 elements in X so that's 2^{20} = 1048576 possibilities for B ⊆ X if there's no restriction on B. However, since B cannot be disjoint with set A, there's only 2^{20} - 2^{10} possibilities left.

5 0
2 years ago
(x – 10) + (3x – 6) =<br> please someone help?
lyudmila [28]

Answer:

4x-4

Step-by-step explanation:

x-10+3x+6=4x-4

Hope helps :3

7 0
3 years ago
Read 2 more answers
A boat is located a sea level. A scuba diver is 80 feet along the surface of the water from the boat and 30 feet below thw water
Sauron [17]

Given :

A boat is located a sea level. A scuba diver is 80 feet along the surface of the water from the boat and 30 feet below the water surface.

A fish is 20 feet along the horizontal plane from the scuba diver and 10 feet below the scuba diver.

To Find :

The slope between the scuba diver and fish.

Solution :

Horizontal distance between diver and fish is 20 feet.

Fish is 10 feet below the scuba diver.

Slope between scuba diver and fish is :

tan\ \theta = \dfrac{10}{20}\\\\tan\ \theta = 0.5

Therefore, the slope between the scuba diver and fish is 0.5 .

6 0
2 years ago
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