In the above diagram, the block is at static equilibrium on the ground. What is the value of the force exerted by the ground on
the block if the force due to gravity is 12 newtons?
A.
20 newtons
B.
12 newtons
C.
-12 newtons
D.
-20 newtons
E.
0 newtons
A.
20 newtons
B.
12 newtons
C.
-12 newtons
D.
-20 newtons
E.
0 newtons
1 answer:
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Answer:
(a) Charge density σ=6.6375×10²nC/m²
(b) Total charge Q=1.47×10²nC
Explanation:
Given Data
A=47.0 cm =0.47 m
Electric field E=75.0 kN/C
To find
(a) Charge density σ
(b)Total Charge Q
Solution
For (a) charge density σ
From Gauss Law we know that
Φ=Q/ε₀.......eq(i)
Where
Φ is electric flux
Q is charge
ε₀ is permittivity of space
And from the definition of flux
Φ = EA
The flux is electric field passing perpendicularly through the surface
Put the this Φ in equation(i)
EA =Q/ε₀
where Q(charge)=σA
EA=(σA)/ε₀
E=σ/ε₀
σ=ε₀E
σ=6.6375×10²nC/m²
For (b) total charge Q
Q=σA
Answer:
Explanation:
The universal law of gravitation is defined as:
(1)
Where G is the gravitational constant, M and m are the masses of the two objects and r is the distance between them.
The centripetal force can be found by means of Newton's second law:
(2)
Since it is a circular motion, the acceleration can be defined as:
(3)
Where v is the velocity and r is the orbital radius.
Replacing equation (3) in equation (2) it is gotten:
(4)
Hence,
Then, v can be isolated:
So the relationship between speed and orbital radius is given by the expression