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max2010maxim [7]
4 years ago
12

What is the weight of a bag that has the mass of 18.0kg

Physics
2 answers:
Novay_Z [31]4 years ago
8 0
39.6832 pounds would be your answer

ehidna [41]4 years ago
7 0
Weight of bag is equals to mass of bag=18.0 kg
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A train travelling at a speed of 108km/h.how much distance is it traveling every second ?
Nesterboy [21]
Hey there! 

To solve this question, lets convert 108 km/h into meters per second. 

1 km/h is equal to 0.277778 m/s

To convert 108 km/h into m/s, we just multiply 0.277778 by 108. 

0.277778 × 108 = 30.000024

So, the train is travelling at approximately 30 meters per second. 

Thank you!
3 0
4 years ago
Question 1 (1 point)
deff fn [24]

Answer:

Travelled 18 km, they are 6 km from home.

Explanation:

12/2 (halfway) is 6km. So, 6 + 12 would be 18 km, total amount travelled. The total distance of the trip would be 24 km (12 km out, 12km back) if they travelled 12+6 (18km) then they only have 6 km more to go.

5 0
3 years ago
The critical angle of diamond is 24 degrees. What is its refractive index?
jolli1 [7]

Answer:

2.46

Explanation:

From the question given above, the following data were obtained:

Critical angle (C) = 24 °

Refractive index (n) =?

The refractive index of the diamond can be obtained by using the following formula as illustrated below:

Refractive index (n) = 1 / sine [critical angle (C)]

n = 1/sine C

n = 1 / sine 24 °

n = 1/0.4067

n = 2.46

Thus, the refractive index of the diamond is 2.46

3 0
3 years ago
two forces P and Q pass through a point A which is 4 ft to the right of and 3 ft above a moment center O. force P is 200 lb dire
valentinak56 [21]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

The moment of the resultant of these two forces with respect to O 376 lb-ft CCW which is <span>about moment center point O.</span>
6 0
3 years ago
The knee extensors insert on the tibia at an angle of 30 degrees (from the longitudinal axis of the tibia), at a distance of 3 c
Reika [66]

Answer:

the knee extensors must exert 15.87 N

Explanation:

Given the data in the question;

mass m = 4.5 kg

radius of gyration k = 23 cm = 0.23 m

angle ∅ = 30°

∝ = 1 rad/s²

distance of 3 cm from the axis of rotation at the knee r = 3 cm = 0.03 m

using the expression;

ζ = I∝

ζ = mk²∝

we substitute

ζ = 4.5 × (0.23)² × 1

ζ  = 0.23805 N-m

so

from; ζ = rFsin∅

F = ζ / rsin∅

we substitute

F = 0.23805 / (0.03 × sin( 30 ° )

F = 0.23805 / (0.03 × 0.5)

F F = 0.23805 / 0.015

F = 15.87 N

Therefore, the knee extensors must exert 15.87 N

7 0
3 years ago
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