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tester [92]
3 years ago
6

An ideal refrigerator-freezer operates with a cop = 7.0 in a 20°c room. what is the temperature inside the freezer?

Physics
1 answer:
Kay [80]3 years ago
4 0
For an ideal case the temperature should be zero.
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Calculate the drop voltage for a battery of internal resistance 2 ohm and emf of 24 volt
Ivenika [448]

Answer:

<em>The drop voltage is 0.3 V</em>

Explanation:

Electromotive Force EMF

When connecting a battery of internal resistance Ri and EMF ε to an external resistance Re, the current through the circuit is:

\displaystyle i=\frac{\varepsilon }{R_e+R_i}

The battery has an internal resistance of Ro=2 Ω, ε=24 V and is connected to an external resistance of Re=158 Ω. Thus, the current is:

\displaystyle i=\frac{24 }{158+2}

\displaystyle i=\frac{24 }{160}

i = 0.15 A

The drop voltage is the voltage of the internal resistance:

V_i = i.R_i

V_i = 0.15*2

\boxed{V_i = 0.3\ V}

The drop voltage is 0.3 V

3 0
3 years ago
1. Paanong nagbukas ang kamalayan ng mga Filipino tungkol sa kaisipang
klemol [59]

Answer:

yes

Explanation:

7 0
3 years ago
What is the speed over the ground of a mosquito flying 2 m/s relative to the air against a 2 m/s headwind?
salantis [7]

We have that the speed over the ground of a mosquito flying 2 m/s relative to the air against a 2 m/s headwind is

X=0m/s

From the question we are told that

mosquito flying 2 m/s

against a 2 m/s headwind

Generally

The speed over the ground is the Flight Speed minus resistance speed

Generally the equation for the  speed over the ground  is mathematically given as

X=Flight Speed-resistance speed

Therefore

X=2-2

X=0m/s

For more information on this visit

brainly.com/question/22271063?referrer=searchResults

8 0
3 years ago
Read 2 more answers
Step by step process on how to solve this problem
rusak2 [61]

<u>Step-1:</u>  Remember or look up the formula for the force of gravity between two objects.    F = G · m₁ · m₂ / R²

<u>Step-2:</u>  Remember or look up the value of G.<em> </em> G = 6.67 x 10⁻¹¹ m³·kg/s²

<u>Step-3: </u> Write the numbers you know into the formula.

(1.989 x 10²⁰ Newtons) =

(6.67 x 10⁻¹¹ mtr³·kg/s²) · (5.9742 x 10²⁴ kg) · (moon mass) / (3.84 x 10⁸ mtr)²

<u>Step-4:</u>  Sit back, relax, take your time, look this mess over, carefully, end-to-end, and decide how to solve it for (moon mass) .

<u>Step-5:</u> Divide each side by (6.67x10⁻¹¹mtr³·kg/s²)·(5.9742x10²⁴kg)/(3.84x10⁸mtr)²:

Moon mass =

(1.989x10²⁰ Newtons)·(3.84x10⁸ mtr)²/(6.67x10⁻¹¹ mtr³·kg/s²)·(5.9742x10²⁴ kg)

<u>Step-6: </u> Crunch the numbers.  Be careful to KEEP all the units as you go along. When you're done, the units of your answer will be the first instant indication if you made a mistake.  You're looking for the MASS of the moon.  If the answer doesn't have units of 'kg', then that'll be an immediate red flag, telling you that there's been a mistake somewhere.

Moon mass =

(1.989x10²⁰ Newtons)·(3.84x10⁸ mtr)²/(6.67x10⁻¹¹ mtr³·kg/s²)·(5.9742x10²⁴ kg)

Collect the numbers, and collect the units:

Moon mass = (1.989x10²⁰ · (3.84x10⁸)² / (6.67x10⁻¹¹ · 5.9742x10²⁴)

(kg-mtr/s² · mtr²)/(mtr³·kg/s² · kg)

Moon mass = (1.989 · 3.84² x 10³⁶) / (6.67 · 5.9742 x 10¹³)

(kg-mtr/s² · mtr²)/(mtr³·kg/s² · kg)

Moon mass = 0.736 x 10²³ kg

Moon mass = 7.36 x 10²² kg

<u>Step 7: </u> Look it up in a book or online.  See if you're anywhere close.

When I search "moon mass" on Floogle, the first hit says

" 7.348 x 10²² kg " .

yay !  I'm satisfied.

6 0
3 years ago
In what direction do seismic waves carry the energy of an earthquake? a. away from the focus b. toward the focus c. from the sur
luda_lava [24]
When an earthquake strikes usually seismic waves carry the energy outward (a.) With the greatest power at the focus and as the seismic waves travel outward they become more and more weak until they disappear.<span />
6 0
3 years ago
Read 2 more answers
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