All categories

2 years ago

Solving inequalities unit portfolio task 2-3?

Mathematics

1 answer:

Elden [556K]2 years ago

4 0

Answer:

What is the question from Solving inequalities unit portfolio task 2-3?

Step-by-step explanation:

Comment it down below and I will solve it! :D

You might be interested in

Suppose the exponential regression equation for some data is y=3.7772•1.923^x. When x equals 5 what is the predicated value of y

sveticcg [70]

y = 3.7772. 1.923^5 = 99 to nearest whole number

3 0

3 years ago

Regroup. Write the missing numbers. 40 tens = ___ hundreds

Genrish500 [490]

Write the missing numbers. 40 tens = ___ hundreds

40 * 10 = 400

so:

40 tens = 4 hundreds

7 0

1 year ago

In triangle ABC, the side lengths are AB = 13, AC = 21, and BC = x. Write a compound inequality that represents the range of pos

N76 [4]

There is only 1 solution for the length of BC.

We can calculate it using Pythagorean theorem.

We can conclude that triangle's hypotenuse is AC.

$AC^2=AB^2+BC^2$

If that is the case we are looking for a side BC.

$BC=\sqrt{AC^2-AB^2}$

Now put in the data.

$BC=\sqrt{21^2-13^2}=\sqrt{272}=\sqrt{272}\approx\boxed{16.49}$

Hope this helps.

r3t40

7 0

3 years ago

Lim x->-5(((1)/(5)+(1)/(x))/(10+2x))=<br><br>correct answer 1/10x = -1/50<br><br>explain:

slava [35]

Given:

The limit problem is:

$lim_{x\to -5}\dfrac{\dfrac{1}{5}+\dfrac{1}{x}}{10+2x}$

To find:

The value of the given limit problem.

Solution:

We have,

$lim_{x\to -5}\dfrac{\dfrac{1}{5}+\dfrac{1}{x}}{10+2x}$

It can be written as:

$=lim_{x\to -5}\dfrac{\dfrac{x+5}{5x}}{2(5+x)}$

$=lim_{x\to -5}\dfrac{x+5}{5x}\times \dfrac{1}{2(5+x)}$

$=lim_{x\to -5}\dfrac{1}{5x\times 2}$

$=lim_{x\to -5}\dfrac{1}{10x}$

Applying limit, we get

$lim_{x\to -5}\dfrac{1}{10x}=\dfrac{1}{10(-5)}$

$lim_{x\to -5}\dfrac{1}{10x}=\dfrac{1}{-50}$

Therefore, the value of given limit problem is $-\dfrac{1}{50}$ .

6 0

3 years ago

What is the area of the two triangles and the quadrilateral

Art [367]

Answer:

Hope this is correct

8 0

3 years ago