The solutions for the quadratic equation 9x² - 6x + 5 = 0 are A. 2 complex roots
To determine the the type of roots the quadratic equation 9x² - 6x + 5 = 0, we use the quadratic formula to find the roots.
So, for a quadratic equation ax + bx + c = 0, the roots are
With a = 9, b = -6 and c = 5, the roots of our equation are
Since the roots of the equation are (1 + 2i)/3 and (1 - 2i)/3, there are 2 complex roots.
So, the solutions for the quadratic equation 9x² - 6x + 5 = 0 are A. 2 complex roots
Learn more about quadratic equations here:
brainly.com/question/18117039
Answer:
Dear we can't give you an answer without the options.
Step-by-step explanation:
ratios that are equivalent to 6:9 are however
2:3, 6:9, 12:18, 18:27, 24:36, 30:45 I believe.
I’m going with none because it would just be N-W= blank. Is the blank n or w. I mean it could be one of those but I don’t think you know enough about the question for it to be N or W. So I would say none. Sorry if I’m wrong.
6.5 goes in the first box and 5.5 goes in the second box.
Explanation for first box: 13+2 is 15 and half of 15 is 7.5 so you need to take 13 and subtract 7.5. Once you do that, you end up with 6.5
Explanation for second box: (The negative 7 doesn't matter because you want the absolute value) 18+7 is 25 and half of 25 is 12.5. 18-12.5 is 5.5 so the answer would be 5.5
Hello from MrBillDoesMath!
Answer:
csc (90° – x) = sec (x
)
sin (90° – x) = cos (x
)
tan (90° – x) = cot (x)
cos (90° – x) = sin (x
)
cot (90° – x) = tan (x
)
sec (90° – x) = csc (x)
Thank you,
MrB
