Midsegments are line segments that connect the midpoints of a triangle. If we have the condition that QR = NP, we have the equation
3x + 2 = 2x + 16
Solving for x
3x - 2x = 16 - 2
x = 14
Therefore, x is 14. <span />
We have been given an equation of hyperbola
. We are asked to find the center of hyperbola.
We know that standard equation of a vertical hyperbola is in form
, where point (h,k) represents center of hyperbola.
Upon comparing our given equation with standard vertical hyperbola, we can see that the value of h is 6.
To find the value of k, we need to rewrite our equation as:

Now we can see that value of k is
. Therefore, the vertex of given hyperbola will be at point
and option D is the correct choice.
See the attached figure
DB = 4 and DC = 6 , We need to find AD
Using <span>Euclid's theorem for the right triangle
</span><span>
</span><span>∴ DB² = AD * DC
</span><span>
</span><span>∴ 4² = AD * 6
</span><span>
</span><span>∴ 6 AD = 16
</span><span>
</span><span>
</span><span>
∴ AD = 16/6 = 8/3 ≈ 2.67</span>
Answer:
The confidence interval = (7.8 , 8.0)
Step-by-step explanation:
Confidence Interval formula =
Mean ± z × Standard deviation/√n
Mean = 7.9
Standard deviation = 0.9
n = number of samples = 164
z = z score of an 80% confidence interval = 1.282
Confidence Interval = 7.9 ± 1.282 × 0.9/√164
= 7.9 ± 0.0900966432
Confidence Interval
= 7.9 - 0.0900966432
= 7.8099033568
Approximately to 1 decimal place = 7.8
7.9 + 0.0900966432
= 7.9900966432
Approximately to 1 decimal place = 8.0
Therefore, the confidence interval = (7.8 , 8.0)
Answer:
60
Step-by-step explanation:
140 = 80 + z
z = 60