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satela [25.4K]
1 year ago
13

I need helppp I’ll give Brainliest this is geometry btwSOMEONE HELP?!!!!

Mathematics
1 answer:
vodka [1.7K]1 year ago
6 0

By using the fact that the two triangles are equivalent, we will find that the value of n must be 18.4

<h3></h3><h3>How to find the length of n?</h3>

Here we can see that the horizontal line divides the triangle in such a way that the left and right sides are divided in two halfs. (we can see this because both parts have the same symbol on them)

Also both of these triangles are equivalent, so:

if x is the measure of each part in the right side we can write the equivalent relation

11.3/x = (n + 4.2)/(2x)

Now wen solve this for n:

(11.3/x)*2x = (n + 4.2)

22.6 = n + 4.2

22.6 - 4.2 = n

18.4 = n

Learn more about equivalent triangles:

brainly.com/question/2217700

#SPJ1

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Answer:

the probability that the mean student loan debt for these people is between $31000 and $33000 is 0.1331

Step-by-step explanation:

Given that:

Mean = 30000

Standard deviation = 9000

sample size = 100

The probability that the mean student loan debt for these people is between $31000 and $33000 can be computed as:

P(31000 < X < 33000) = P( X \leq 33000) - P (X \leq 31000)

P(31000 < X < 33000) = P( \dfrac{X - 30000}{\dfrac{\sigma}{\sqrt{n}}} \leq \dfrac{33000 - 30000}{\dfrac{9000}{\sqrt{100}}}    )- P( \dfrac{X - 30000}{\dfrac{\sigma}{\sqrt{n}}} \leq \dfrac{31000 - 30000}{\dfrac{9000}{\sqrt{100}}}    )

P(31000 < X < 33000) = P( Z \leq \dfrac{33000 - 30000}{\dfrac{9000}{\sqrt{100}}}    )- P(Z \leq \dfrac{31000 - 30000}{\dfrac{9000}{\sqrt{100}}}    )

P(31000 < X < 33000) = P( Z \leq \dfrac{3000}{\dfrac{9000}{10}}}) -P(Z \leq \dfrac{1000}{\dfrac{9000}{10}}})

P(31000 < X < 33000) = P( Z \leq 3.33)-P(Z \leq 1.11})

From Z tables:

P(31000 < X

P(31000 < X

Therefore; the probability that the mean student loan debt for these people is between $31000 and $33000 is 0.1331

8 0
3 years ago
Y=-1/9x-4 Which of the following is the equation of a line that is parallel?
fenix001 [56]

Any line with a slope of -1/9 will be parallel

4 0
3 years ago
A rectangular park of length 60 m breadth 50 m encloses w volleyball court of length 18 m and breadth 10 m. Find the area of the
Zanzabum

Given

A rectangular park of length 60 m breadth 50 m encloses with volleyball court of length 18 m and breadth 10 m.

To find:

The area of the park excluding the court at the rate of Rs 110 per square meter.​

Solution:

Area of a rectangle is:

Area=length \times breadth

Area of whole park is:

A_1=60 \times 50

A_1=3000

Area of volleyball court is:

A_2=18 \times 10

A_2=180

Now, the area of the park excluding the court is:

A=A_1-A_2

A=3000-180

A=2820

Therefore, the area of the park excluding the court is 2820 square meter.

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3 years ago
On monday caroline spent 2/3hour riding her bike and 1 3/4 doing homework how many more hours did caroline spend doing homework
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2/3 hour is 40 minutes. 1 3/4 hour is 1 hour and 45 minutes. So she spent 1 hour and 5 minutes or 1 1/12 hour longer doing homework.
8 0
3 years ago
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Show all work to multiply (6+square root -64)(3-square root -16)
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Answer:

50

Step-by-step explanation:

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>> -32i² + [24i - 24i] + 18

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>>> 32 + 18 = 50

Information on Imaginary Numbers

√-1 = i

-1 = i²

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1 = i⁴ [And every other exponent that is a multiple of 4; this cycle then repeats itself every time you go up one number at a time]

If you are ever in need of assistance, do not hesitate to let me know by subscribing to my You-Tube channel [USERNAME: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.

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3 years ago
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