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skelet666 [1.2K]
2 years ago
9

How i did? In livada sunt 12 mere am cules 6. Cate mera au ramas?

Mathematics
1 answer:
vovikov84 [41]2 years ago
7 0

Answer:

72

Step-by-step explanation:

12x6=72

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Romashka-Z-Leto [24]

Answer:

36x + 63

Step-by-step explanation:

8 0
3 years ago
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Which equation has the same solution as this equation?
lesya [120]

Answer:

3rd Option is correct.

Step-by-step explanation:

Given Equation:

x² - 16x + 12 = 0

First We need to find solution of the given equation.

x² - 16x + 12 = 0

here, a = 1   , b = -16  &  c = 12

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-(-16)\pm\sqrt{(-16)^2-4(12)}}{2}

x=\frac{16\pm\sqrt{256-48}}{2}

x=\frac{16\pm\sqrt{208}}{2}

x=\frac{16\pm4\sqrt{13}}{2}

x=8+2\sqrt{13}\:\:andx=8-2\sqrt{13}

Now,

Option 1).

( x - 8 )² = 144

x - 8 = ±√144

x - 8 = ±12

x = 8 + 12 = 20   and x = 8 - 12 = -4

Thus, This is not correct Option.

Option 2).

( x - 4 )² = 4

x - 4 = ±√4

x - 4 = ±2

x = 4 + 2 = 6   and x = 4 - 2 = 2

Thus, This is not correct Option.

Option 3).

( x - 8 )² = 52

x - 8 = ±√52

x - 8 = ±2√13

x  = 8 + 2√13   and x = 8 - 2√13

Thus, This is correct Option.

Option 4).

( x - 4 )² = 16

x - 4 = ±√116

x - 4 = ±4

x = 4 + 4 = 8  and x = 4 - 4 = 0

Thus, This is not correct Option.

Therefore, 3rd Option is correct.

8 0
3 years ago
A family of four spent $104 for tickets to a concert on Friday and they spent $140 for tickets to dinner theater on Saturday.Wha
BigorU [14]

Answer:

$61

Step-by-step explanation:

To determine the cost per person to attend these events, you have to add the cost of the tickets for the concert plus the cost of the tickets for dinner theater. After finding the total amount that was spent, you have to divide this by 4 that is the number of people:

Total cost= $104+$140

Total cost= $244

Cost per person= $244/4

Cost per person= $61

According to this, the cost per person to attend these events is $61.

5 0
4 years ago
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(50 points) need help.
tatiyna

Answer:

I believe it is 127ft²

Step-by-step explanation:

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2 years ago
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Which expression is equivalent to 4C0m430 + 4C1m331 + 4C2m232 + 4C3m133 + 4C4m034? 4x4 + 12x3 + 54x2 + 108x + 81 4x4 + 12x3 + 54
Ymorist [56]

Answer:

its the last one

Step-by-step explanation:

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