X^2 - 8x = (x - 4)^2 - 16
we add 16 to give x^2 - 8x + 16 which is a perfect square
x^2 - 8x + 16 = (x - 4)^2
answer is 16
Remove the negative exponent by rewriting x^-3 as 1/x^3
(9)/(1/x^3)
multiply the numerator by the reciprocal of the denominator
9x^3
Answer:
21
Step-by-step explanation:
Answer:
1.= 27
2.=13.3...
Step-by-step explanation:
