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creativ13 [48]
3 years ago
9

You are conducting an experiment with a spring. You attach hanging masses one after the other, increasing gradually the extensio

n of the spring. When do you know that you have reached the limit of elasticity of the spring?
Select all that apply.

A.) By adding more and more masses, the spring is completely stretched out.
B.) By removing the masses before adding a new one, the spring has not fully regained its initial length.
C.) By adding more and more masses, the spring is no longer stretching linearly.
D.) By adding more and more masses, the spring is broken in half.
Physics
1 answer:
Lunna [17]3 years ago
6 0

You will know that the limit of elasticity of the spring has been reached by adding more and more masses, the spring is no longer stretching linearly.

According to Hooke's law, within the elastic limit of a spring, the stretching force is directly proportional to the extension.

As long as this is true, the spring will continue to stretch linearly as more masses are added.

When the elastic limit of the spring has been attained, adding more and more masses no longer leads to a linear stretching of the spring.

Learn more: brainly.com/question/10991960

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serg [7]

Velocity of plane is given as

v_1 = 2.50 * 10^2 km/h towards north

v_2 = 75 km/h towards south east

we can write the two velocity in vector form

v_1 = 2.50 * 10^2 \hat j

v_2 = 75 cos45 \hat i - 75 sin45 \hat j

now the net velocity will be given as

v_{net} = v_1 + v_2

v_{net} = 250\hat j + 53.03 \hat i - 53.03 \hat j

v_{net} = 53.03\hat i + 196.97 \hat j

so the resultant velocity will be given as

v_{net} = \sqrt{53.03^2 + 196.97^2}

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and the angle of velocity will be

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\theta = tan^{-1}\frac{196.97}{53.03} = 74.9 degree

3 0
4 years ago
You grab a hot cookie sheet out of the oven this is an example of ______ energy transfer.
Maru [420]
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3 years ago
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3 years ago
A physical therapy exercise has a person shaking a 5.00 kg weight up and down rapidly. if the barbell is moving at 4.50 m/s, wha
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The magnitude of the force required to stop the weight in 0.333 seconds is 67.6 N.

<h3>Magnitude of required force to stop the weight</h3>

The magnitude of the force required to stop the weight in 0.333 seconds is calculated by applying Newton's second law of motion as shown below;

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Thus, the magnitude of the force required to stop the weight in 0.333 seconds is 67.6 N.

Learn more about force here: brainly.com/question/12970081

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What is the magnitude of g at a height above Earth's surface where free-fall acceleration equals 6.5m/s^2?
prohojiy [21]

You've given the answer, right there in your question.

The "magnitude of gravity" is described in terms of the acceleration
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We can also notice that the figure you gave is about 0.66 of the
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4 years ago
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