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liraira [26]
3 years ago
11

For which property has Marvin forgotten to use an SI unit of measurement? A shore length B high temperature C low temperature D

annual precipitation
Physics
1 answer:
jasenka [17]3 years ago
3 0
The correct answer is B :) 
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If a car moves with a uniform speed of 2m/s in a circle of radius 0.4m, what is its angular speed?
REY [17]

Answer:

The car's angular speed is \frac{rad}{s}.

Explanation:

Angular velocity is usually measured with \frac{radians}{sec}, so I'm going to use that to answer your question.

The relationship between tangential velocity and angular velocity (ω)  is given by:

V = \omega R

Using the values from the question, we get:

2 \frac{m}{s} = \omega (0.4m)

\omega = 5 \frac{rad}{s}

Therefore, the car's angular speed is 5 \frac{rad}{s}.

Hope this helped!

3 0
3 years ago
According to this graph, which statement describes how the amount of iron changes over time in the reaction
VashaNatasha [74]
The graph shows the production of Fe, from the graph that it increases rapidly and then slowly increases.<span>The answer is a! (:
</span>
5 0
4 years ago
A bullet of mass 0.016 kg traveling horizontally at a speed of 280 m/s embeds itself in a block of mass 3 kg that is sitting at
ivanzaharov [21]

(a) 1.49 m/s

The conservation of momentum states that the total initial momentum is equal to the total final momentum:

p_i = p_f\\m u_b + M u_B = (m+M)v

where

m = 0.016 kg is the mass of the bullet

u_b = 280 m/s is the initial velocity of the bullet

M = 3 kg is the mass of the block

u_B = 0 is the initial velocity of the block

v = ? is the final velocity of the block and the bullet

Solving the equation for v, we find

v=\frac{m u_b}{m+M}=\frac{(0.016 kg)(280 m/s)}{0.016 kg+3 kg}=1.49 m/s

(b) Before: 627.2 J, after: 3.3 J

The initial kinetic energy is (it is just the one of the bullet, since the block is at rest):

K_i = \frac{1}{2}mu_b^2 = \frac{1}{2}(0.016 kg)(280 m/s)^2=627.2 J

The final kinetic energy is the kinetic energy of the bullet+block system after the collision:

K_f = \frac{1}{2}(m+M)v^2=\frac{1}{2}(0.016 kg+3 kg)(1.49 m/s)^2=3.3 J

(c) The Energy Principle isn't valid for an inelastic collision.

In fact, during an inelastic collision, the total momentum of the system is conserved, while the total kinetic energy is not: this means that part of the kinetic energy of the system is losted in the collision. The principle of conservation of energy, however, is still valid: in fact, the energy has not been simply lost, but it has been converted into other forms of energy (thermal energy).

4 0
4 years ago
Which has more momentum, a 2.0 kg dog at 41 m/s or a 75 kg pony at 1.0 m/s?
Nesterboy [21]

Answer:

The dog has more momentum than the pony.

Explanation:

To solve this problem, we must remember the formula for calculating momentum, which is given below:

momentum = p = m*v

where m represents the mass of the object and v represents the velocity of the object

Using this knowledge, let's calculate the momentum for the dog and the pony.

Dog: p = m*v = (2kg)*(41 m/s) = 82 kg*m/s

Pony: p = m*v = (75kg)*(1 m/s) = 75 kg*m/s

Since 82 > 75, we can conclude that the dog has more momentum.

Hope this helps!

3 0
4 years ago
Anyones good in gr5 science pls help me
oee [108]

Answer:

1. A

sound can't travel through vacuum only

6 0
3 years ago
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