Set up
Let the dimes = d
Let the pennies = p
Let the quarters = q
Equations
You cannot mean that the pennies and dimes have equal numbers. That would mean that each had 21.5 members. Now could you mean that the dime and penny amount could be the same with 43 coins that total 4.00. Four dollars means that you need 40 dimes alone. It must mean that you are including quarters.
p + d + p = 43 (1)
p = d (2)
p +10d +25q = 451 (3)
Note how this last equation = was derived. You have to multiply the dimes by 10 and he quarters by 100 and the total by 100 to get the numbers all in pennies.
Put the results of 2 into 1.
2p + q = 43 (4)
You need to modify equation 3 as well.
p + 10p + 25q = 451
11p + 25q = 451 (5)
Solve the new equations
2p + q = 43 (4)
11p + 25q = 451 (5)
Multiply 4 by 25
25(2p- + q = 43)
50p + 25q = 1075 (6) Subtract (5) from (6)
<u>11p + 25q = 451
</u>39p = 624 Divide by 39
p = 624 / 39
p = 16
Since the pennies and dimes are equal there are 16 dimes
p + d + q = 43
16 + 16 + q = 43
32 + q = 43
q = 11
Check
16 + 10*16 + 11*25 = ?
16 + 160 + 275 = ?
451 = ?
Nice problem. Thanks for posting.
Answer:
1035 feet
Step-by-step explanation:
Given:
OB = 900 m
«BOH = 49°
Find BH:
BH/BO =tan 49
BH = BO tan 49
BH = 900 * 1.15
BH = 1035
Answer:
The most tickets were written on Saturday .On Saturday 325 tickets were issued
Step-by-step explanation:
The average number of traffic tickets issued in a city on any given day Sunday-Saturday can be approximated by

Where x represents the number of days after Sunday
T(x) represents the number of traffic tickets issued.
Sunday = x=0
Monday = x=1
Tuesday = x=2
Wednesday = x=3
Thursday = x =4
Friday = x=5
Saturday = x=6
Substitute x= 0

On Sunday 37 tickets were issued
Substitute x= 1

On Monday 115 tickets were issued
Substitute x= 2

On Tuesday 181 tickets were issued
Substitute x= 3

On Wednesday 235 tickets were issued
Substitute x= 4

On Thursday 277 tickets were issued
Substitute x= 5

On Friday 307 tickets were issued
Substitute x= 6

On Saturday 325 tickets were issued
Hence the most tickets were written on Saturday .On Saturday 325 tickets were issued

Step-by-step explanation:
Given

So

Hence,

Keywords: functions, Function composition
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