Using PV=nRT or the ideal gas equation, we substitute n= 15.0 moles of gas, V= 3.00L, R equal to 0.0821 L atm/ mol K and T= 296.55 K and get P equal to 121.73 atm. The Van der waals equation is (P + n^2a/V^2)*(V-nb) = nRT. Substituting a=2.300L2⋅atm/mol2 and b=0.0430 L/mol, P is equal to 97.57 atm. The difference is <span>121.73 atm- 97.57 atm equal to 24.16 atm.</span>
The theoretical yield of NaBr given that 2.36 moles of FeBr₃ reacts is 7.08 moles
<h3>Balanced equation </h3>
2FeBr₃ + 3Na₂S → Fе₂S₃ + 6NaBr
From the balanced equation above,
2 moles FeBr₃ reacted to produce 6 moles of NaBr
<h3>How to determine the theoretical yield of NaBr</h3>
From the balanced equation above,
2 moles FeBr₃ reacted to produce 6 moles of NaBr
Therefore,
2.36 moles FeBr₃ will react to produce = (2.36 × 6) / 2 = 7.08 moles of NaBr
Therefore,
Thus, the theoretical yield of NaBr is 7.08 moles
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A compound is analyzed and found to contain 22.10%Al, 25.40%P, and 52.50%O
Let the total mass of compound = 100g
The mass of Aluminum = 22.10 g
Moles of Al = mass / atomic mass = 22.10 /23= 0.96
The mass of P = 25.40 g
Moles of P = 25.40 / 31 = 0.819
The mass of oxygen = 52.50 g
Moles of oxygen = 52.50 / 16= 3.28
The mole ratio of the two elements will be
Al = 0.96/0.819 = 1.17
P = 0.819/0.819 = 1
O = 3.28 / 0.819 = 4
The whole number ratio will be 1 : 1 : 4
So formula will be AlPO4
Answer:
B. pOH = 14 - pH and D. pH = 14 - pOH.
Explanation:
Hello,
In this case, we must remember that pH and pOH are referred to a measure of acidity and basicity respectively, since pH accounts for the concentration of H⁺ and pOH for the concentration of OH⁻ in a solution. In such a way, since the maximum scale is 14, we say that the addition between the pH and pOH must be 14:
Therefore, the correct answers are B. pOH = 14 - pH and D. pH = 14 - pOH since the both of them are derived from the previous definition.
Best regards.
It easier to remove electrons from a large element(bottom of the periodic table) because there further away from the nucleus.
