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Maurinko [17]
2 years ago
15

Considering the patterns you have noticed in this activity, which statement best explains why a compound with the molecular form

ula CH3 doesn't exist in nature?
A. Hydrogen typically needs four bonds to reach a noble gas configuration.
B. Carbon needs more than just three bonds to reach a noble gas configuration. C. The chemical CH3 does not react with other substances because of its high stability.
D. CH3 has three double bonds, which fails to give it a noble gas configuration​
Chemistry
1 answer:
AveGali [126]2 years ago
5 0

Answer:

The answer is B

Explanation:

I had the same question and I chose B and it was correct.

You might be interested in
A. Calculate the empirical formula of a molecule with percent compositions: 55.3% potassium (K), 14.6% phosphorus (P), and 30.1%
Otrada [13]
The way you calculate the empirical formula is to firstly assume 100g. To find each elements moles you take each elements percentage listed, times it by one mole and divide it by its atomic mass. (ex: moles of K =55.3g x 1 mole/39.1g, therefore there is 1.41432225 moles of Potassium) Once you’ve completed this for every element you list each elements symbol beside it’s number of moles and divide by the smallest number because it can only go into its self once. After you’ve done this, you’ve found your empirical formula, which is the simplest whole number ratio of atoms in a compound. I’ve added an example of a empirical question I completed last semester :)

6 0
3 years ago
Read 2 more answers
PCl3(g) + Cl2(g) ⇋ PCl5(g) Kc = 91.0 at 400 K. What is the [Cl2] at equilibrium if the initial concentrations were 0.24 M for PC
Dmitry_Shevchenko [17]

Answer:

[Cl₂] in equilibrium is 1.26 M

Explanation:

This is the equilibrium:

PCl₃(g) + Cl₂(g) ⇋ PCl₅(g)

Kc = 91

So let's analyse, all the process:

                PCl₃(g)        +        Cl₂(g)     ⇋        PCl₅(g)

Initially     0.24 M                 1.50M                 0.12 M

React           x                           x                         x

Some amount of compound has reacted during the process.

In equilibrium we have

              0.24 - x                  1.50 - x                  0.12 + x

As initially we have moles of product, in equilibrium we have to sum them.

Let's make the expression for Kc

Kc = [PCl₅] / [Cl₂] . [PCl₃]

91 = (0.12 + x) / (0.24 - x) ( 1.50 - x)

91 = (0.12 + x) / (0.36 - 0.24x - 1.5x + x²)          

91 (0.36 - 0.24x - 1.5x + x²) = (0.12 + x)

32.76 - 158.34x + 91x² = 0.12 +x

32.64 - 159.34x + 91x² = 0

This a quadratic function:

a = 91; b= -159.34; c = 32.64

(-b +- √(b² - 4ac)) / 2a

Solution 1 = 1.5

Solution 2 = 0.23 (This is our value)

So [Cl₂] in equilibrium is 1.50 - 0.23 = 1.26 M

5 0
3 years ago
What structure do all of these elements have in common?
Dmitrij [34]
The answer is c because of going left to right
7 0
3 years ago
Read 2 more answers
Propenoic acid, C3H4O2, is a reactive organic liquid that is used in the manufacturing of plastics, coatings, and adhesives. An
Shkiper50 [21]

Answer:

C = 39%

H = 5.43%

Explanation:

Firstly, we calculate the number of moles of each.

For carbon, we use carbon iv oxide

Mass here = 0.636g

Number of moles of carbon iv oxide = mass of carbon iv oxide ÷ molar mass of carbon iv oxide. Molar mass = 44g/mol

Number of moles = 0.636 ÷ 44 = 0.014mole

Since 1 mole of carbon iv oxide contains 1 mole carbon, 0.014 mole of carbon iv oxide is also produced.

Mass of carbon = 0.014 × 12 = 0.173g, where 12 is the a.m.u of carbon.

For hydrogen, we use water .

Mass of water = 0.220g

No of moles of water = 0.22 ÷ 18 = 0.012 mole

1 mole of water has two moles of hydrogen, thus the amount of hydrogen produced = 0.012 × 2 = 0.024mole

Mass of hydrogen produced = 0.024 × 1 = 0.024g

The percentage composition are as follows:

Carbon = 0.173/0.442 × 100 = 39%

Hydrogen = 0.024/0.442 × 100 = 5.43%

5 0
3 years ago
The combustion of ethyne, shown below unbalance, produces heat which can be used to weld metals:
Andreyy89

Answer:

3.69 g

Explanation:

Given that:

The mass m = 325 g

The change in temperature ΔT = ( 1540 - 165)° C

= 1375 ° C

Heat capacity c_p = 0.490 J/g°C

The amount of heat required:

q = mcΔT

q =  325 × 0.490 × 1375

q = 218968.75 J

q = 218.97 kJ

The equation for the reaction is expressed as:

C_2H_{2(g)} + 5O_{2(g)} \to 2CO_{2(g)} + H_2O_{(g)}   \ \   \ \ \  \Delta H^o_{reaction} = -1544 \ kJ

Then,

1 mole of the ethyne is equal to 26 g of ethyne required for 1544 kJ heat.

Thus, for 218.97 kJ, the amount of ethyne gas required will be:

= \dfrac{26 \ g}{1544 \ kJ} \times 218.97 \ kJ

= 3.69 g

3 0
3 years ago
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