The solute normally doesn't dissolve and sinks to the bottom of the container. However, some saturated solutions can become super-saturated for a given temperature and pressure, by altering the conditions without allowing solute to precipitate.
Answer:
the axis is tilted at 98 degrees
Explanation:
Uranus is blue, not green; it has an atmosphere of hydrogen and helium, not methane. While it does have an icy cold temperature, that's not a very unusual characteristic for an outer planet. However, the tilt of the axis is unusual; no other planet is tilted almost completely on its side!
Answer:
1.181 × 10²⁴ molecules CO₂
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Explanation:
<u>Step 1: Define</u>
86.34 g CO₂
<u>Step 2: Identify Conversion</u>
Avogadro's Number
Molar Mass of C - 12.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol
<u>Step 3: Convert</u>
<u />
= 1.18141 × 10²⁴ molecules CO₂
<u>Step 4: Check</u>
<em>We are given 4 sig figs. Follow sig fig rules and round.</em>
1.18141 × 10²⁴ molecules CO₂ ≈ 1.181 × 10²⁴ molecules CO₂
Answer:
Cotton and Jute
Explanation:
Cotton and jute are the two most important fibre crops of India. Cotton provides the basic raw material to cotton textile industry. Cotton is a kharif crop which requires 6 to 8 months to mature. The main cotton producing states are Gujarat, Maharashtra and Andhra Pradesh. Next to cotton, jute is the second important fibre crop of India. India is one of the principle producers of jute in the world. The major jute producing states of India are West Bengal, Assam, Bihar, Odisha, Andhra Pradesh and Meghalaya.
Answer:
3.8 cm
Explanation:
Given data
- Initial pressure (P₁): 3.2 atm
- Initial volume (V₁): 65 cm³
Volume of a sphere: V = 4/3 × π × r³ = 4/3 × π × (2.5 cm)³ = 65 cm³
- Initial temperature (T₁): 5.4°C + 273.15 = 278.6 K
- Final pressure (P₂): 1.0 atm
- Final temperature (T₂): 25.0°C + 273.15 = 298.2 K
We can find the final volume using the combined gas law.

The final radius of the bubble is:
V = 4/3 × π × r³
223 cm³ = 4/3 × π × r³
r = 3.8 cm