<u>Answer:</u> The mass of methanol that must be burned is 24.34 grams
<u>Explanation:</u>
We are given:
Amount of heat produced = 581 kJ
For the given chemical equation:
By Stoichiometry of the reaction:
When 764 kJ of heat is produced, the amount of methanol reacted is 1 mole
So, when 581 kJ of heat will be produced, the amount of methanol reacted will be =
To calculate mass for given number of moles, we use the equation:
Moles of methanol = 0.7605 moles
Molar mass of methanol = 32 g/mol
Putting values in above equation, we get:
Hence, the mass of methanol that must be burned is 24.34 grams
Each name is a given number of objects
[Ar] 3s^23p^6 since Ar is in period 3 and have all the orbitals filled with electrons
Atomic number is Z. Z=number of protons, so Z=11
199.5 g of sucrose is needed to make 665 ml of 30 % weight by volume percent solution.
<h3>What is percent solution?</h3>
Percent solution is defined as a convenient way to record concentration of solution.It is a expression which relates solute to solvent as,mass of solute/mass of solution ×100.There are two types of percentage solutions percent weight by volume and percent volume by volume .Advantages of using percent solutions is that molecular weight of compound is not required.
This example is percent weight by volume where mass of solute is calculated as,%(w/v)= mass of solute/mass of solution×100
substitution of values gives,30×665/100=199.5 g
Thus ,199.5 g of sucrose is required to make 665 ml of 30 % sucrose solution.
Learn more about percent solutions,here:
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