Answer:
Step-by-step explanation:
Created Sequences
S1: 10 20 40 80 150
s2:24 20
The first term that appears in both sequences is the second term. Both of them equal 20.
I don't think you have to go any further once you get the first term.
Method
S1: Multiply by 2 starting with 10.
10*2 = 20
20*2 = 40
S2: Start at 24 and subtract 4
24 - 4 = 20
20 - 4 = 16
16 - 4 = 12
3x - y + z = 5 . . . (1)
x + 3y + 3z = -6 . . . (2)
x + 4y - 2z = 12 . . . (3)
From (2), x = -6 - 3y - 3z . . . (4)
Substituting for x in (1) and (3) gives
3(-6 - 3y - 3z) - y + z = 5 => -18 - 9y - 9z - y + z = 5 => -10y - 8z = 23 . . (5)
-6 - 3y - 3z + 4y - 2z = 12 => y - 5z = 18 . . . (6)
(6) x 10 => 10y - 50z = 180 . . . (7)
(5) + (7) => -58z = 203
z = 203/-58 = -3.5
From (6), y - 5(-3.5) = 18 => y = 18 - 17.5 = 0.5
From (4), x = -6 - 3(0.5) - 3(-3.5) = -6 - 1.5 + 10.5 = 3
x = 3, y = 0.5, z = -3.5
Answer:
28 pounds
Step-by-step explanation:
We have a total of 5 boxes, now we know that each box weighs 9 pounds, therefore:
Total weight = 5 * 9 = 45 pounds
Which means there are 45 pounds in total.
We are told that the limit is exceeded by 17 pounds. To find the limit weight, it is necessary to subtract the total weight and the excess:
45-17 = 28 pounds
Therefore, the maximum weight allowed per shipment is 28 pounds.
