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Scrat [10]
3 years ago
10

What is the molar concentration of a solution prepared by dissolving 8.63 g of Ba(NO3)2 (molar mass = 261.35 g/mol) to a total v

olume of 250.0 mL?
What is the molar concentration of a solution prepared by diluting 10.0 mL of the solution in Question #1 to a total volume of 50.00 mL?
Chemistry
1 answer:
PilotLPTM [1.2K]3 years ago
7 0

Answer:

我實際上不知道答案,我只是為了點數而這樣做,哈哈,祝你好運哈哈

Explanation:

我實際上不知道我實際上不知道答案,我只是為了點數而這樣做,哈哈,祝你好運哈哈我實際上不知道答案,我只是為了點數而這樣做,哈哈,祝你好運哈哈答案,我只是為了點數而這樣做,哈哈,祝你好運哈哈

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An exergonic reaction __________ free energy, and an endergonic reaction __________ free energy.
Rashid [163]
An exergonic reaction proceeds with net release of free energy.
An endergonic reaction absorbs free energy
8 0
2 years ago
Which of the following is the ground state of an atom? Which is its excited state? Which is an impossible electron configuration
Rus_ich [418]

For this specific problem, these would be the answer to the following choices:

a. excited

b. ground

c. impossible

I am hoping that these answers have satisfied your queries and it will be able to help you, thank you and have a nice day.

3 0
3 years ago
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Which of the following measurements has three significant figures?
Free_Kalibri [48]

The correct answer is <u>C: 0.510 m</u>

<u></u>

N I C E - D A Y!

8 0
2 years ago
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What is the wavelength of the matter wave associated with an electron (me= 9.1 x 10-31 kg) moving with a speed of 2.5 x 107 m/s?
riadik2000 [5.3K]
And h value is constant 6.624 x 10^-34

3 0
3 years ago
If the mass percentage composition of a compound is 72.1% Mn and 27.9% O, its empirical formula is
mojhsa [17]

Answer:

MnO- Manganese Oxide

Explanation:

Empirical formula: This is the formula that shows the ratio of elements

present in a  

compound.

   

How to determine Empirical formula

1. First arrange the symbols of the elements present in the compound

alphabetically to  determine the real empirical formula. Although, there

are exceptions to this rule, E.g H2So4

2. Divide the percentage composition by the mass number.

3. Then divide through by the smallest number.

4. The resulting answer is the ratio attached to the elements present in

a compound.

           

                                                                              Mn                         O    

                         

% composition                                                      72.1                      27.9    

                       

Divide by mass number                                       54.94                     16  

                                 

                                                                               1.31                      1.74    

                       

Divide by the smallest number                         1.31                      1.31                          

                                                                               1                    1.3

                                                 

The resulting ratio is 1:1

 

Hence the Empirical formula is MnO, Manganese oxide

8 0
3 years ago
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