Answer:
Abiotic
Explanation:
Its because it includes water, sunlight, tempature and soil
The freezing point of a solution containing 5. 0 grams of KCl and 550.0 grams of water is - 0.45°C
Using the equation,
Δ
= i
m
where:
Δ = change in freezing point (unknown)
i = Van't Hoff factor
= freezing point depression constant
m = molal concentration of the solution
Molality is expressed as the number of moles of the solute per kilogram of the solvent.
Molal concentration is as follows;
MM KCl = 74.55 g/mol
molal concentration = 
molal concentration = 0.1219m
Now, putting in the values to the equtaion Δ = im we get,
Δ = 2 × 1.86 × 0.1219
Δ = 0.4536°C
So, Δ of solution is,
Δ
= 0.00°C - 0.45°C
Δ = - 0.45°C
Therefore,freezing point of a solution containing 5. 0 grams of KCl and 550.0 grams of water is - 0.45°C
Learn more about freezing point here;
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<h3>
Answer:</h3>
#1. Balanced equation: 2C₅H₅ + Fe → Fe(C₅H₅)₂
#2. Type of reaction: Synthesis reaction
<h3>
Explanation:</h3>
- Balanced equations are equations that obey the law of conservation of mass.
- When an equation is balanced the number of atoms of each element is equal on both side of the equation.
- Equations are balanced by putting appropriate coefficients on the reactants and products.
- In our case, we are going to put coefficients 2, 1 and 1.
- Thus, the balanced equation will be;
2C₅H₅ + Fe → Fe(C₅H₅)₂
- This type of a reaction is known as synthesis reaction, in which two or more reactants or compounds combine to form a single compound or product.
Answer:
I am looking for this as well. Can someone please help!
Explanation:
Answer:
a.) 22.4 L Ne.
Explanation:
It is known that every 1.0 mol of any gas occupies 22.4 L.
For the options:
<em>It represents </em><em>1.0 mol of Ne.</em>
<em />
using cross multiplication:
1.0 mol occupies → 22.4 L.
??? mol occupies → 20 L.
The no. of moles of (20 L) Ar = (1.0 mol)(20 L)/(22.4 L) = 0.8929 mol.
using cross multiplication:
1.0 mol occupies → 22.4 L.
??? mol occupies → 2.24 L.
<em>The no. of moles of (2.24 L) Xe </em>= (1.0 mol)(2.24 L)/(22.4 L) = <em>0.1 mol.</em>
- So, the gas that has the largest number of moles at STP is: a.) 22.4 L Ne.
