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11111nata11111 [884]
1 year ago
12

Find the measure of DE. 2x+7 4(x-3)

Mathematics
1 answer:
Masja [62]1 year ago
6 0

Answer:

x=1

Step-by-step explanation:

ktftyk

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The grassy area of a playground has a side length of x and a side of width of x + 3 what is the area of the playground?
Kipish [7]

Answer:

A

Step-by-step explanation:

We assume this playground is a rectangle. The area of a rectangle is of the form: A = lw, where l is the length and w is the width.

Here, the length is l = x and the width is w = x + 3. So, plug these in:

A = lw

A = x(x + 3)

Expand this out:

A = x² + 3x

The answer is thus A.

4 0
3 years ago
Read 2 more answers
You weld two piece's of steel together. The toral thickness is 33/64 inch. If one piece of steel is 9/32 inch thick, how thick t
Anon25 [30]

Subtract the thickness of the known piece from the total thickness.

Because they have different denominators rewrite them to have the same.

9/32 x 2 = 18/64

Now you have 33/64 - 18/64 = 15/64

The other piece is 15/64 inch thick.

4 0
2 years ago
Round to the nearest tenth.
inessss [21]

Answer: Angle A = 53.9 degrees

Step-by-step explanation: We have a right angled triangle with two sides clearly given and one angle to be calculated. If the angle to be calculated is angle A, then having angle A as our reference angle, line AC (10 units) is the adjacent, line CB is the opposite while line AB (17 units) is the hypotenuse. Having been given the adjacent and the hypotenuse, we can now use the trigonometric ratio as follows;

CosA = adjacent/hypotenuse

CosA = 10/17

CosA = 0.5882

By use of the calculator or table of values,

A = 53.97

Approximately to the nearest tenth,

A = 53.9 degrees

6 0
3 years ago
The outer diameter of a spherical shell is 36 pie cm³and its inner diameter is 9 cm. Find the volume of the metal contained the
Leona [35]

Answer:

may be 11.460

sorry to say this but I'm not sure bout my answer

(ー_ー✿)

4 0
2 years ago
3. Solve the system using elimination (not substitution or matrices). negative 2 x plus y minus 2 z equals negative 8A N D7 x pl
riadik2000 [5.3K]

Elimination Method

\begin{gathered} -2X+Y-2Z=-8 \\ 7X+Y+Z=-1 \\ 5X+2Y-Z=-9 \end{gathered}

If we multiply the equation 3 by (-1) we obtain this:

\begin{gathered} -2X+Y-2Z=-8 \\ 7X+Y+Z=-1 \\ -5X-2Y+Z=9 \end{gathered}

If we add them we obtain 0, therefore there are infinite solutions. So, let's write it in terms of Z

1. Using the 3rd equation we can obtain X(Y,Z)

\begin{gathered} 5X=-9-2Y+Z \\ X=\frac{-9-2Y+Z}{5} \\  \end{gathered}

2. We can replace this value of X in the 1st and 2nd equations

\begin{gathered} -2\cdot(\frac{-9-2Y+Z}{5})+Y-2Z=-8 \\ 7\cdot(\frac{-9-2Y+Z}{5})+Y+Z=-1 \end{gathered}

3. If we simplify:

\begin{gathered} \frac{-9Y+12Z-63}{5}=-1 \\ \frac{9Y-12Z+18}{5}=-8 \end{gathered}

4. We can obtain Y from this two equations:

\begin{gathered} Y=-\frac{-12Z+58}{9} \\  \end{gathered}

5. Now, we need to obtain X(Z). We can replace Y in X(Y,Z)

\begin{gathered} X=\frac{-9-2Y+Z}{5} \\ X=\frac{-9-2(-\frac{-12Z+58}{9})+Z}{5} \end{gathered}

6. If we simplify, we obtain:

X=\frac{-3Z+7}{9}

7. In conclusion, we obtain that

(X,Y,Z) =

(\frac{-3Z+7}{9},-\frac{-12Z+58}{9},Z)

8 0
10 months ago
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