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1 year ago

Find the measure of DE. 2x+7 4(x-3)

Mathematics

1 answer:

Masja [62]1 year ago

6 0

Answer:

x=1

Step-by-step explanation:

ktftyk

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Plssss help quick i need it for sum important

Vanyuwa [196]

(a) The product of $(2x-4)\ and\ (3x^2-x+4)$ is calculated to be $=6x^3-14x^2+12x-16$

(b)The product of $(2x-4) \ and\ (3x^2-x+4)\$ is not equal to the product of $(4x-2)\ and\ (3x^2-x+4)$

Step-by-step explanation:

(a)

$(2x-4)(3x^2-x+4)\\\\=(2x.3x^2)+(2x.-x)+(2x.4)+(-4.3x^2)+(-4.-x)+(-4.4)\\\\=6x^3-2x^2+8x-12x^2+4x-16\\\\=6x^3-14x^2+12x-16$

$(4x-2)(3x^2-x+4)\\\\=(4x.3x^2)+(4x.-x)+(4x.4)+(-2.3x^2)+(-2.-x)+(-2.4)\\\\=12x^3-4x^2+16x-6x^2+2x-8\\\\=12x^3-10x^2+18x-8$

The product of $(2x-4) \ and\ (3x^2-x+4)\$ is not equal to the product of $(4x-2)\ and\ (3x^2-x+4)$

7 0

3 years ago

I put 41 points.

Anna71 [15]

It is the first equation, 3x-y=-7.
It is the only equation that both sets of points satisfy as true.

3 0

3 years ago

Write your answer in standard form. (6x+7) (x-8)

WITCHER [35]

Answer:

First one is d and second one is c

Step-by-step explanation:

(6x+7)(x-8)

(6x)(x) = 6x^2

(6x)(-8) = -48

(7)(x) = 7x

(7)(-8) = -56

Add all like terms together and you get choice d.

(w+3)(w-3)

(w)(w) = w^2

(w)(-3) = -3w

(3)(w) = 3w

(3)(-3) = -9

Add all like terms together and you get choice c

5 0

3 years ago

Read 2 more answers

a directed line segment AB on he coordinate plane starts from A (3, 0) and ends at B (12, -9). Find the y coordinate of point C

Anastaziya [24]

Answer:

The answer to your question is: y = -54 / 11

Step-by-step explanation:

Data

A (3, 0)

B (12, -9)

r = 6/5

Formula

y = $\frac{y1 + ry2}{1 +r}$

y = $\frac{0 + (6/5)(-9)}{1 + 6/5}$

y = $\frac{-54/ 5}{11/5}$

y = -54/11

5 0

3 years ago

Read 2 more answers

Find the missing value: Question 37

Annette [7]

I want to say A but im not sure

7 0

3 years ago