Y = mx + bsolve for m solve for x
1 answer:
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So to find the discriminant of a quadratic equation, the formula is b² - 4ac with a = x² coefficient, b = x coefficient, and c = constant. In this case, our equation is
Firstly, solve the multiplications and the exponents:
Next, subtract and we find that our discriminant is 0.
*Additional Info: Since the discriminant is zero, this means that this quadratic equation has 1 real solution.
First set up equation
x times y=xy
so
xy=-29
and
x+y=1
subtract x from both sides
y=1-x
subsitute 1-x for y in first equation
x(1-x)=-29
distribute
x-x^2=-29
add x^2 to both sides
x=-29+x^2
subtract x from both sides
0=x^2-x-29
so we can use the quadratic formula to solve for x if the equation=0 and it is in ax^2+bx+c form so
if
ax+bx+c=0 then x=
that means x=
or x=
so
x^2-x-29
a=1
b=-1
c=-29
=![\frac{ +1-\sqrt{1^2-(-116)} }{2(1)}=\frac{ +1-\sqrt{1^2+116} }{2}=\frac{ +1-\sqrt{117} }{2}= \frac{1-10.816653826392}{2} = [tex] \frac{-9.816653826392}{2}= -4.908326913196](https://tex.z-dn.net/?f=%5Cfrac%7B%20%2B1-%5Csqrt%7B1%5E2-%28-116%29%7D%20%7D%7B2%281%29%7D%3D%5Cfrac%7B%20%2B1-%5Csqrt%7B1%5E2%2B116%7D%20%7D%7B2%7D%3D%5Cfrac%7B%20%2B1-%5Csqrt%7B117%7D%20%7D%7B2%7D%3D%20%5Cfrac%7B1-10.816653826392%7D%7B2%7D%20%3D%20%5Btex%5D%20%5Cfrac%7B-9.816653826392%7D%7B2%7D%3D%20-4.908326913196)
the second number is
the two numbers are
5.908326913196 and
-4.908326913196
x times y=xy
so
xy=-29
and
x+y=1
subtract x from both sides
y=1-x
subsitute 1-x for y in first equation
x(1-x)=-29
distribute
x-x^2=-29
add x^2 to both sides
x=-29+x^2
subtract x from both sides
0=x^2-x-29
so we can use the quadratic formula to solve for x if the equation=0 and it is in ax^2+bx+c form so
if
ax+bx+c=0 then x=
x^2-x-29
a=1
b=-1
c=-29
the second number is
the two numbers are
5.908326913196 and
-4.908326913196