You have that situation with ANY base that's less than ' 1 '.
Examples:
(0.9)² = 0.81 (90% of the base)
(7/8)² = 0.765625 (87.5% of the base)
(1/2)² = 1/4 (50% of the base)
(0.1)² = 0.01 (10% of the base)
Each of these results is less than the base, and with
higher positive powers, they keep getting smaller.
Answer:
y is located at (1,1)
the measure is 56
c - congruent
Step-by-step explanation:
If its rotated at its vortex then its rotating around the coordinates of Y
If the angle is rotated then the value of the angle does not change
Answer:
it would be 2
Step-by-step explanation:
take the equation and do 8 - 6 and then you get the answer
Answer:
G
Step-by-step explanation:
Supposing a normal distribution, we find that:
The diameter of the smallest tree that is an outlier is of 16.36 inches.
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We suppose that tree diameters are normally distributed with <u>mean 8.8 inches and standard deviation 2.8 inches.</u>
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In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:
- The Z-score measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.<u>
</u>
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In this problem:
- Mean of 8.8 inches, thus
. - Standard deviation of 2.8 inches, thus
.
<u />
The interquartile range(IQR) is the difference between the 75th and the 25th percentile.
<u />
25th percentile:
- X when Z has a p-value of 0.25, so X when Z = -0.675.




75th percentile:
- X when Z has a p-value of 0.75, so X when Z = 0.675.




The IQR is:

What is the diameter, in inches, of the smallest tree that is an outlier?
- The diameter is <u>1.5IQR above the 75th percentile</u>, thus:

The diameter of the smallest tree that is an outlier is of 16.36 inches.
<u />
A similar problem is given at brainly.com/question/15683591