There is one zero in the ten thousands place.
There is another zero in the hundreds place.
Both of them have the value of zero.
I would say A.$54.32 because it is the only option that is less than 55.56
M = (t+1)/(t-3)
m(t-3) = t+1
mt-3m = t+1
(m-1)t = 3m+1
t = (3m+1)/(m-1)
Answer:
- 32.823 kJ
- 190.4 kJ
- 260.00 kJ
- 180.012 kJ
Step-by-step explanation:
The conversion factor for food energy or thermochemical calorimetry* is ...
1 calorie = 4.184 J
1000 calorie = 4.184 kJ
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a. 7845 cal = 7845·4.184 J = 32,823 J = 32.823 kJ
b. 4.55·10^4 cal = 4.55·10^4·4.184 J = 1.904·10^5 J = 190.4 kJ
c. 62.142 kcal = 62.142·4.184 kJ = 260.00 kJ
d. 43,024 cal = 43,024·4.184 J = 180,012 J = 180.012 kJ
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* The thermochemical calorie is defined in terms of the heat capacity of water. An international calorie of 4.1868 J is defined in terms of energy, without respect to the heat capacity of water.
