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2 years ago

9

PLSSS HELP IF YOU TURLY KNOW THISS

1 answer:

I am Lyosha [343]2 years ago

6 0

Answer:

75%

Step-by-step explanation:

multiply the fraction by 100 to find the percent:

3/4 * 100 = 3*25 = 75

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a construction crew built 4 1/2 miles of Road and 3 3/8 days. What is the unit rate in miles per day? Write your answer as a fra

sineoko [7]

The construction crew took $3\frac{3}{8}$ days to build $4\frac{1}{2}$ miles of road.

Therefore, in 1 day, the crew built $\frac{4\frac{1}{2} }{3\frac{3}{8} }$ miles of road

= $\frac{\frac{9}{2} }{\frac{27}{8} } =\frac{9}{2}times\frac{8}{27}=\frac{4}{3}$ miles of road

Thus, the required rate is $\frac{4}{3}$ miles or $1\frac{1}{3}$ miles per day.

5 0

3 years ago

jake is getting a new phone! he buys the service is $50 per month. write the funtion that would represent on how much jake sends

I am Lyosha [343]

Since x=months,

50x=y

Where x is the number of months times the monthly charge. Y is just the output, or end value.

I hope this helps!
~kaikers

4 0

3 years ago

Solve<br><img src="https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B1%7D%7Bp%7D%20%2B%20%5Cdfrac%7B1%7D%7Bq%7D%20%2B%20%5Cdfrac%7B1%7D

Nostrana [21]

Answer:

$\displaystyle \begin{cases} \displaystyle {x} _{1} = - p \\ \displaystyle x _{2} = - q \end{cases}$

Step-by-step explanation:

we would like to solve the following equation for x:

$\displaystyle \frac{1}{p} + \frac{1}{q} + \frac{1}{x} = \frac{1}{p + q + x}$

to do so isolate $\frac{1}{x}$ to right hand side and change its sign which yields:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{1}{p + q + x} - \frac{1}{x}$

simplify Substraction:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{x - (q + p + x)}{x(p + q + x)}$

get rid of only x:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{ - (q + p )}{x(p + q + x)}$

simplify addition of the left hand side:

$\displaystyle \frac{q + p}{pq} = \frac{ - (q + p )}{x(p + q + x)}$

divide both sides by q+p Which yields:

$\displaystyle \frac{1}{pq} = \frac{ -1}{x(p + q + x)}$

cross multiplication:

$\displaystyle x(p + q + x) = - pq$

distribute:

$\displaystyle xp + xq + {x}^{2} = - pq$

isolate -pq to the left hand side and change its sign:

$\displaystyle xp + xq + {x}^{2} + pq = 0$

rearrange it to standard form:

$\displaystyle {x}^{2} + xp + xq + pq = 0$

now notice we end up with a <u>quadratic</u><u> equation</u> therefore to solve so we can consider <u>factoring</u><u> </u><u>method</u><u> </u><u> </u>to use so

factor out x:

$\displaystyle x( {x}^{} + p ) + xq + pq = 0$

factor out q:

$\displaystyle x( {x}^{} + p ) +q (x + p)= 0$

group:

$\displaystyle ( {x}^{} + p ) (x + q)= 0$

by <em>Zero</em><em> product</em><em> </em><em>property</em> we obtain:

$\displaystyle \begin{cases} \displaystyle {x}^{} + p = 0 \\ \displaystyle x + q= 0 \end{cases}$

cancel out p from the first equation and q from the second equation which yields:

$\displaystyle \begin{cases} \displaystyle {x}^{} = - p \\ \displaystyle x = - q \end{cases}$

and we are done!

3 0

3 years ago

Plzzzzzzzzzzzzzzzzzz

sveta [45]

The first column. The rule for that column is y = x * -4.

8 0

3 years ago

HELPP my work is due soon plus i don’t understand :(

Mashcka [7]

Answer:

4. B

5.

Step-by-step explanation:

8 0

2 years ago