1. y = 4x - 3
2. y = -x + 4
3. y = 1/3x +1
4. y = ----
5. y = 1/7x + 2
6. y = -4x + 2.75
7. y = 3x + 5
8.
9.
10.
11.
12.
Answer: if you are going to put it like p^2-m^2 no one going to have that answer so I need the p and the m like for example the p=5 and the m=4
Step-by-step explanation: so it going to be like
Evaluate for m=4,p=5
5^2−4^2
=9
So I can’t answer how you put it
Find m∠BOC, if m∠MOP = 110°.
Answer:
m∠BOC= 40 degrees
Step-by-step explanation:
A diagram has been drawn and attached below.
- OM bisects AOB into angles x and x respectively
- ON bisects ∠BOC into angles y and y respectively
- OP bisects ∠COD into angles z and z respectively.
Since ∠AOD is a straight line
x+x+y+y+z+z=180 degrees
We are given that:
m∠MOP = 110°.
From the diagram
∠MOP=x+2y+z
Therefore:
x+2y+z=110°.
Solving simultaneously by subtraction
x+2y+z=110°.
We obtain:
x+z=70°
Since we are required to find ∠BOC
∠BOC=2y
Therefore from x+2y+z=110° (since x+z=70°)
70+2y=110
2y=110-70
2y=40
Therefore:
m∠BOC= 40 degrees
Answer:
62°
Step-by-step explanation:
The angle R inscribes the arc FQ, so using the property of inscribed angles in a circle, we have that:
m∠R = mFQ / 2
The arc FQ is the sum of the arcs FP and PQ, so we have:
mFQ = mFP + mPQ = 11x + 7 + 60 = 11x + 67
Now, with the first equation, we have:
12x + 1 = (11x + 67) / 2
24x + 2 = 11x + 67
13x = 65
x = 5°
So we have that mFP = 11x + 7 = 55 + 7 = 62°
Answer:
69 people got in free over the 2 days
Step-by-step explanation:
6742/175=38
5487/175=31
31+38=69
