All categories

3 years ago

Determine the domain and range of the function F= {(2,1),(30,-7),(34,1),(54,0)

Mathematics

1 answer:

Arisa [49]3 years ago

4 0

Answer:

Domain = 2,30,34,54

Range = 1,-7,1,0

Step-by-step explanation:

Domain = x input

Range = y output

Your function is f(x) = y.

You might be interested in

I just need help on the question circled below. (I need the answer ASAP.)

77julia77 [94]

2.5+ 2.5= 5 miles i think

6 0

3 years ago

GIVING A BRAINLIST PLZZ ASAP

Jobisdone [24]

Answer:

(b) Mr. Sánchez's class earned more money.

(a) $\displaystyle [42, 37] → [j, p]$

Step-by-step explanation:

{79 = p + j

{118,17 = 1,65p + 1,36j

−25⁄34[118,17 = 1,65p + 1,36j]

{79 = p + j

{−86 121⁄136 = −1 29⁄136p - j >> New Equation

__________________________

$\displaystyle \frac{-7\frac{121}{136}}{-\frac{29}{136}} = \frac{-\frac{29}{136}p}{-\frac{29}{136}}$

$\displaystyle 37 = p$ [Plug this back into both equations above to get the j-value of 42]; $\displaystyle 42 = j$

The next step is to plug the solution into the BOTTOM EQUATION to calculate the total money earned for each class:

Sánchez's class

$\displaystyle 61,05 = [37][1,65]$

Altogether, thirty-seven fruit pies cost $61,05.

Kelly's class

$\displaystyle 57,12 = [42][1,36]$

Altogether, forty-two bottles of fruit juice cost $57,12.

* Based on the calculation, it is perfectly clear that Mr. Sánchez's class earned more money by $3,93:

$\displaystyle 3,93 = -57,12 + 61,05$

I am delighted to assist you anytime my friend!

6 0

3 years ago

What is the range of the following list of ordered pairs? (-4,-2),(3,5),(0,4)

Lelu [443]

Range is the y-value. The y-value in an ordered pair is the second number

(x, y)

So pick out all the y-values from the given ordered pairs:

(-4, -2) -> -2
(3, 5) -> 5
(0, 4) -> 4

Now put them together.

The range is {-2, 4, 5}

4 0

4 years ago

A manager at a local manufacturing company has been monitoring the output of one of the machines used to manufacture chromium sh

denpristay [2]

Answer:

0.682 = 68.2% probability that the average length of these 16 shells will be between 116 and 120 centimeters when the machine is operating "properly".

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Normally distributed with a mean of 118 centimeters and a standard deviation of 8 centimeters.

This means that $\mu = 118, \sigma = 8$

Sample of 16 shells

This means that $n = 16, s = \frac{8}{\sqrt{16}} = 2$

What is the probability that the average length of these 16 shells will be between 116 and 120 centimeters when the machine is operating "properly?"

This is the pvalue of Z when X = 120 subtracted by the pvalue of Z when X = 116.

X = 120

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{120 - 118}{2}$

$Z = 1$

$Z = 1$ has a pvalue of 0.841

X = 116

$Z = \frac{X - \mu}{s}$

$Z = \frac{116 - 118}{2}$

$Z = -1$

$Z = -1$ has a pvalue of 0.159

0.841 - 0.159 = 0.682

0.682 = 68.2% probability that the average length of these 16 shells will be between 116 and 120 centimeters when the machine is operating "properly".

3 0

3 years ago

Can someone please help me with math.

Morgarella [4.7K]

Answer:

the answer is a. y=-2x-5

6 0

3 years ago