Answer:
<h2>
<u>Solution :-</u></h2>
i) Given expressions are 2a + b, a + b
On Subtracting second expression form the first expression
=> (2a+b) -(a+b)
=> 2a+b-a-b
=> (2a-a)+(b-b)
=> a+0
=> a
ii) Given expressions are - 2b + 2c, b + 3c
On Subtracting second expression form the first expression
=> (- 2b + 2c)-( b + 3c)
=> -2b+2c-b-3c
=> (-2b-b)+(2c-3c)
=> -3b-c
iii) Given expressions are 5a + b, - 6b + 2a
On Subtracting second expression form the first expression
=> (5a + b)-(- 6b + 2a )
=> 5a+b+6b-2a
=> (5a-2a)+(b+6b)
=> 3a+7b
iv) Given expressions are a³-1+a, 3a-2a²
On Subtracting second expression form the first expression
=> (a³-1+a)-(3a-2a²)
=> a³-1+a-3a+2a²
=> a³-1-2a+2a²
=> a³+2a²-2a+1
v) Given expressions are p + 2,1
On Subtracting second expression form the first expression
=> (p+2)-(1 )
=> p+2-1
=> p+1
vi) Given expressions are x + 2y + z , -x - y - 3z
On Subtracting second expression form the first expression
=> (x + 2y + z )-(-x - y - 3z )
=> x+2y+z+x+y+3z
=> (x+x)+(2y+y)+(z+3z)
=> 2x+3y+4z
vii) Given expressions are 3a²-8ab-2b²,3a²-4ab+6b²
On Subtracting second expression form the first expression
=> (3a²-8ab-2b²)-(3a²-4ab+6b²)
=> 3a²-8ab-2b²-3a²+4ab-6b²
=> (3a²-3a²)+(-8ab+4ab)+(-2b²-6b²)
=> 0+(-4ab)+(-8b²)
=> -4ab-8b²
viii) Given expressions are 4pq-6p²-2q²,9p²
On Subtracting second expression form the first expression
=> (4pq-6p²-2q²)-(9p²)
=> 4pq-6p²-2q²-9p²
=> 4pq-15p²-2q²
ix) Given expressions are 10abc,2a²+2abc-4b²
On Subtracting second expression form the first expression
=> (10abc)-(2a²+2abc-4b²)
=> 10abc-2a²-2abc+4b²
=> 8abc-2a²+4b²
x) Given expressions are a²+ab+c², a²-d²
On Subtracting second expression form the first expression
=> (a²+ab+c²)-( a²-d²)
=> a²+ab+c²-a²+d²
=> (a²-a²)+ab+c²+d²
=> 0+ab+c²+d²
=> ab+c²+d²
Hope this helps!!
