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2 years ago

What is the place value of the 1 in the number 6.213

Mathematics

1 answer:

DochEvi [55]2 years ago

5 0

Answer:

The hundredths place

Expanation

6 is in the one's place

2 is in the theth's place

1 is in the hundredth's place

3 is in the thousandth's place

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A movie theater charges $9.50 for adults and $4.50 for children. For a recent showing of a movie, the theater sold 33 tickets an

choli [55]

Answer:

The number of children's tickets sold was 31 and the number of adult tickets sold was 2

Step-by-step explanation:

Let

x ---> the number of children's tickets sold

y ---> the number of adult tickets sold

we know that

the theater sold 33 tickets

$x+y=33$ -----> equation A

the theater made a total of $158.50

$4.50x+9.50y=158.50$ ----> equation B

Solve the system by graphing

Remember that the solution of the system is the intersection point both graphs

using a graphing tool

The solution is the point (31,2)

see the attached figure

therefore

The number of children's tickets sold was 31 and the number of adult tickets sold was 2

5 0

3 years ago

Identify the functions that are continuous on the set of real numbers and arrange them in ascending order of their limits as x t

Studentka2010 [4]

Answer:

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

Step-by-step explanation:

1. $f(x)=\frac{x^2+x-20}{x^2+4}$

The denominator of f is defined for all real values of x

Therefore, the function is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x^2+x-20}{x^2+4}=\frac{25+5-20}{25+4}=\frac{10}{29}=0.345$

3. $h(x)=\frac{3x-5}{x^2-5x+7}$

$x^2-5x+7=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function h is defined for all real values.

$\lim_{x\rightarrow 5}\frac{3x-5}{x^2-5x+7}=\frac{15-5}{25-25+7}=\frac{10}{7}=1.43$

2. $g(x)=\frac{x-17}{x^2+75}$

The denominator of g is defined for all real values of x.

Therefore, the function g is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x-17}{x^2+75}=\frac{5-17}{25+75}=\frac{-12}{100}=-0.12$

4. $i(x)=\frac{x^2-9}{x-9}$

x-9=0

x=9

The function i is not defined for x=9

Therefore, the function i is not continuous on the set of real numbers.

5. $j(x)=\frac{4x^2-7x-65}{x^2+10}$

The denominator of j is defined for all real values of x.

Therefore, the function j is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{4x^2-7x-65}{x^2+10}=\frac{100-35-65}{25+10}=0$

6. $k(x)=\frac{x+1}{x^2+x+29}$

$x^2+x+29=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function k is defined for all real values.

$\lim_{x\rightarrow 5}\frac{x+1}{x^2+x+29}=\frac{5+1}{25+5+29}=\frac{6}{59}=0.102$

7. $l(x)=\frac{5x-1}{x^2-9x+8}$

$x^2-9x+8=0$

$x^2-8x-x+8=0$

$x(x-8)-1(x-8)=0$

$(x-8)(x-1)=0$

$x=8,1$

The function is not defined for x=8 and x=1

Hence, function l is not defined for all real values.

8. $m(x)=\frac{x^2+5x-24}{x^2+11}$

The denominator of m is defined for all real values of x.

Therefore, the function m is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{x^2+5x-24}{x^2+11}=\frac{25+25-24}{25+11}=\frac{26}{36}=\frac{13}{18}=0.722$

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

6 0

3 years ago

A scale of 0.5 inches to 2 feet was used for a model of the goal posts on a football field. If the model was 1 1/2 in high and 5

Paraphin [41]

The actual height is: 1 1/2 * 2 = 3 feet
The actual length is: 5 1/8 * 2 = 10.25 feet

hope this helps you.

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Csf%5Cfrac%7B%7B96%7D%5E%7B84%7D%7D%7B%7B96%7D%5E%7B82%7D%7D%3D..." id="TexFormula1" title="

NNADVOKAT [17]

<h3>☁️ Learn Math With Me-!</h3>

$\sf\frac{{96}^{84}}{{96}^{82}}=... \\$

$\sf = {96}^{84} \div {96}^{82}$

$\sf = {96}^{84 - 82}$

$\sf = {96}^{2}$

$\sf = 96 \times 96$

$\sf = 9.216$

Correct Me If I'm Wrong :)

6 0

2 years ago

Read 2 more answers

What is equivalent to <img src="https://tex.z-dn.net/?f=%283%5E6%293" id="TexFormula1" title="(3^6)3" alt="(3^6)3" align="absmid

kherson [118]

For this case we must indicate an expression equivalent to:

$(3 ^ 6) ^ 3$

For properties of powers we have to:

$(a ^ n) ^ m = a ^ {n * m}$

So, the above expression can be rewritten as:

$(3 ^ 6) ^ 3 = 3^{6*3} = 3^{18}$

Thus, the resulting expression is: $3^{ 18}$

Answer:

$3^{ 18}$

Option D

8 0

3 years ago