Ron earned $95 in interest for leaving $1,000 in an account for 3 years. What was his rate? Round to the nearest hundredth (2 de
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Answer:
The 80% confidence interval for the mean per capita income in thousands of dollars is between $21.3 and $21.9.
Step-by-step explanation:
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of .
So it is z with a pvalue of , so
Now, find the margin of error M as such
In which is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 21.6 - 0.3 = $21.3.
The upper end of the interval is the sample mean added to M. So it is 21.6 + 0.3 = $21.9.
The 80% confidence interval for the mean per capita income in thousands of dollars is between $21.3 and $21.9.
Answer:
Hey there!
A=
A=216
Hope this helps :)