The right answer for the question that is being asked and shown above is that: "B. X^2 = 5.85 p = 0.88." The answer that would be the appropriate type of test to investigate our hypothesis is that <span>"B. X^2 = 5.85 p = 0.88." This is the correct answer.</span>
Answer:
None
Step-by-step explanation:
Question 1
probability between 2.8 and 3.3
The graph of the normal distribution is shown in the diagram below. We first need to standardise the value of X=2.8 and value X=3.3. Standardising X is just another word for finding z-score
z-score for X = 2.8

(the negative answer shows the position of X = 2.8 on the left of mean which has z-score of 0)
z-score for X = 3.3

The probability of the value between z=-0.73 and z=0.49 is given by
P(Z<0.49) - P(Z<-0.73)
P(Z<0.49) = 0.9879
P(Z< -0.73) = 0.2327 (if you only have z-table that read to the left of positive value z, read the value of Z<0.73 then subtract answer from one)
A screenshot of z-table that allows reading of negative value is shown on the second diagram
P(Z<0.49) - P(Z<-0.73) = 0.9879 - 0.2327 = 0.7552 = 75.52%
Question 2
Probability between X=2.11 and X=3.5
z-score for X=2.11

z-score for X=3.5

the probability of P(Z<-2.41) < z < P(Z<0.98) is given by
P(Z<0.98) - P(Z<-2.41) = 0.8365 - 0.0080 = 0.8285 = 82.85%
Question 3
Probability less than X=2.96
z-score of X=2.96

P(Z<-0.34) = 0.3669 = 36.69%
Question 4
Probability more than X=3.4

P(Z>0.73) = 1 - P(Z<0.73) = 1-0.7673=0.2327 = 23.27%
Answer:
AE = 11.76 units
Step-by-step explanation:
For better understanding of the solution, see the attached figure :
Given : E ∈ AB, m∠ABC = m∠ACE, AB = 34 and AC = 20
To find AE :
In ΔABC and ΔACE,
m∠ABC = m∠ACE ( Given )
∠A = ∠A ( Common angle for both the triangles )
By AA postulate of similarity of triangles, ΔABC ~ ΔACE
So, proportion of the corresponding will be equal.

Hence, AE = 11.76 units
Since it is evaluate you don't put an equal sign and you just simplify the problem. Start by plugging in 6 for n and then simplify.
48/6 is 8