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2 years ago

How many grams of aluminum would be in 3.0 moles of aluminum?

Chemistry

1 answer:

Mariana [72]2 years ago

3 0

Answer:

Explanation:

The number of grams of Aluminum in one mole of Aluminum is the number under the element's symbol, on the Periodic Table of the elements, which is 26.981. With compounds, water, for example, is an oxygen and two hydrogens. So you would add 15.999 to 2(1.0079). You multiply the hydrogen's number by two because there's two of them.

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Distinguish a substance from a mixture. give two examples of each

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substance is matter of particular or definite chemical constitution ex: iron, methane
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2 years ago

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It's called a breeze

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2 years ago

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Determine the theoretical yield of HCl if 60.0 g of BC13 and 37.5 g of H20 are reacted according to the following balanced react

Pie

Answer : The theoretical yield of HCl is, 56.1735 grams

Explanation : Given,

Mass of $BCl_3$ = 60 g

Mass of $H_2O$ = 37.5 g

Molar mass of $BCl_3$ = 117 g/mole

Molar mass of $H_2O$ = 18 g/mole

Molar mass of $HCl$ = 36.5 g/mole

First we have to calculate the moles of $BCl_3$ and $H_2O$ .

$\text{Moles of }BCl_3=\frac{\text{Mass of }BCl_3}{\text{Molar mass of }BCl_3}=\frac{60g}{117g/mole}=0.513moles$

$\text{Moles of }H_2O=\frac{\text{Mass of }H_2O}{\text{Molar mass of }H_2O}=\frac{37.5g}{18g/mole}=2.083moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$BCl_3(g)+3H_2O(l)\rightarrow H_3BO_3(s)+3HCl(g)$

From the balanced reaction we conclude that

As, 1 mole of $BCl_3$ react with 3 mole of $H_2O$

So, 0.513 moles of $BCl_3$ react with $3\times 0.513=1.539$ moles of $H_2O$

From this we conclude that, $H_2O$ is an excess reagent because the given moles are greater than the required moles and $BCl_3$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $HCl$ .

As, 1 mole of $BCl_3$ react to give 3 moles of $HCl$

So, 0.513 moles of $BCl_3$ react to give $3\times 0.513=1.539$ moles of $HCl$

Now we have to calculate the mass of $HCl$ .

$\text{Mass of }HCl=\text{Moles of }HCl\times \text{Molar mass of }HCl$

$\text{Mass of }HCl=(1.539mole)\times (36.5g/mole)=56.1735g$

Therefore, the theoretical yield of HCl is, 56.1735 grams

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2 years ago

suffixes Refer to the word parts table that you made for the words in Section 2 containing the suffix -ic. Use each of the words

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Explanation:

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2 years ago

How many moles of CaO are needed to react with excess water to produce 370g of calcium hydroxide?

never [62]

Answer:

5 moles

Explanation:

CaO+H20--> Ca(OH)2

mass 280 90 370g

RFM 56 18 74

moles 5 5 5

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3 years ago