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Anuta_ua [19.1K]
2 years ago
13

Calculate the molarity of each of the following

Chemistry
1 answer:
Alenkasestr [34]2 years ago
8 0

Answer:

a. 1.21M

b. 0.119M

c. 0.00496M

Explanation:

Molarity, M, is an unit of concentration defined as the ratio between moles of solute and liters of solution:

a. 4.35 mol LiCl / 3.60L = 1.21M

b. 29.43gC6H12O6 * (1mol / 180.16g) = 0.1634moles / 1.37L = 0.119M

<em>Molar mass C6H12O6: 180.16g/mol</em>

c. 34.5mg NaCl = 0.0345g * (1mol / 58.44g) = 5.9x10⁻⁴moles / 0.1191L = 0.00496M

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alexdok [17]

Answer:

Answers are bellow.

Explanation:

The element with electron configuration 1s22s22p63s1 belong I A group in the periodic table and it is sodium because it loses one electron.

We have periodic table in attachments.

Sodium is a chemical element with the symbol Na and atomic number 11. It is a soft, silvery-white, highly reactive metal. Sodium is an alkali metal, being in group 1 of the periodic table, because it has a single electron in its outer shell, which it readily donates, creating a positively charged ion—the Na+ cation. Its only stable isotope is 23Na.

The free metal does not occur in nature, and must be prepared from compounds.

It is soft metal, reactive and with a low melting point.

8 0
3 years ago
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How can an atom that has seven valence electrons complete its outermost level
GaryK [48]
It can form a covalent bond with a hydrogen bond that has one valence electron to have eight valence electrons and become stable.
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3 years ago
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From the enthalpies of reaction H2(g)+F2(g)→2HF(g)ΔH=−537kJ C(s)+2F2(g)→CF4(g)ΔH=−680kJ 2C(s)+2H2(g)→C2H4(g)ΔH=+52.3kJ calculate
DIA [1.3K]

Answer:

\Delta H for the given reaction is -2486.3 kJ

Explanation:

The given equation can be written as a combination of the following equation:

2H_{2}(g)+2F_{2}(g)\rightarrow 4HF(g)  ; \Delta H_{1}= (2\times -537kJ)=-1074 kJ

2C(s)+4F_{2}(g)\rightarrow 2CF_{4}(g)  ;  \Delta H_{2}=(2\times -680kJ)=-1360kJ

C_{2}H_{4}(g)\rightarrow 2C(s)+2H_{2}(g)  ;  \Delta H_{3}=-52.3kJ

-----------------------------------------------------------------------------------

C_{2}H_{4}(g)+6F_{2}(g)\rightarrow 2CF_{4}(g)+4HF(g)

\Delta H=\Delta H_{1}+\Delta H_{2}+\Delta H_{3}=(-1074-1360-52.3)kJ=-2486.3kJ

6 0
3 years ago
PLEASE HELP!!! The image represents the reaction between a certain number of molecules of N2 and H2.
77julia77 [94]

Answer:

  • <u><em>The leftover reactant is the nitrogen gas, N₂.</em></u>

Explanation:

As per your description:

<u>1. Square on the left: N₂(g)</u>

  • 3 units of two joint circles: this represents 3 molecules of nitrogen gas, N₂(g).

<u>2. Square on the right: H₂(g)</u>

  • 3 units of two joint circles: this represents 3 molecules of hydrogen gas, H₂(g).

<u>3. Reaction</u>

If the maximum possible amount of NH₃ is formed during the reaction, you assume that the reaction goes to completion.

The chemical equation that represents the reaction is:

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That means that 1 molecule (or 1 mol) of N₂(g) reacts with 3 molecules (or 3 moles ) of  H₂(g) to produce 2 molecules (or 2 moles) of NH₃(g).

Since, the squares show that there are 3 molecules of each reactant, the 3 molecules of hydrogen gas will be able to react with 1 molecule of nitrogen gas. When that happens, all the hydrogen gas is consumend and yet two molecules of nitrogen gas will remain unreacted. Hence, the nitrogen gas is the leftover reactant.

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alexdok [17]

Answer:

1) F=5×9.8

F=49

2) F=50×9.8

F=490

3) W= fd

W=10×3

W=30

4 0
2 years ago
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