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Lesechka [4]
2 years ago
6

PLEASE HELP!!!! Find m Will give brainliest for correct answer

Mathematics
1 answer:
kherson [118]2 years ago
8 0

Answer:

r = 5

Step-by-step explanation:

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(3 1/2) (-1 5/7) <br><br><br><br> PLEASE HELP!! SOMEONE PLEASEEEE!!
katen-ka-za [31]

Answer:

-6

Step-by-step explanation:

Use a calculator

8 0
3 years ago
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ANSWER PLEASE...
liraira [26]

Answer: The median is 28208 the mean is 28234.6

Step-by-step explanation:

The mode is the number that is repeated the most there can be more than one mode.

4 0
3 years ago
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Solve the triangle.
vova2212 [387]

9514 1404 393

Answer:

  b = 71 m

  A = 83°

  C = 29°

Step-by-step explanation:

Many calculators can solve triangles. Apps are available for phone and tablet, or on the internet, like the one used here. In general, it takes less time to use one of these than to type your question into Brainly.

Given two sides and the angle between them, the Law of Cosines is the appropriate relation to use for finding the third side.

  b = √(a² +c² -2ac·cos(B))

  b = √(76² +37² -2·76·37·cos(67.75°)) ≈ √5015.48

  b ≈ 70.82005 ≈ 71 . . . meters

__

One a side and its opposite angle are known, the remaining angles are found using the Law of Sines.

  sin(A)/a = sin(B)/b

  A = arcsin(a·sin(B)/b) = arcsin(76·sin(67.75°)/70.82005) ≈ 83.33°

  A ≈ 83°

  C = arcsin(37·sin(67.75°)/70.82005) ≈ 28.92°

  C ≈ 29°

Or, you can find the remaining angle from 180° -68° -83°  = 29°.

3 0
3 years ago
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
sleet_krkn [62]

Answer:

-6re−r [sin(6θ) - cos(6θ)]

Step-by-step explanation:

the Jacobian is ∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ

x = e−r sin(6θ), y = er cos(6θ)

δx/δθ = -6rcos(6θ)e−r sin(6θ), δx/δr = -sin(6θ)e−r sin(6θ)

δy/δθ = -6rsin(6θ)er cos(6θ), δy/δr = cos(6θ)er cos(6θ)

∂(x, y) /∂(r, θ) =  δx/δθ × δy/δr - δx/δr × δy/δθ

= -6rcos(6θ)e−r sin(6θ) × cos(6θ)er cos(6θ) - [-sin(6θ)e−r sin(6θ) × -6rsin(6θ)er cos(6θ)]

= -6rcos²(6θ)e−r (sin(6θ) - cos(6θ)) - 6rsin²(6θ)e−r (sin(6θ) - cos(6θ))

= -6re−r (sin(6θ) - cos(6θ)) [cos²(6θ) + sin²(6θ)]

= -6re−r [sin(6θ) - cos(6θ)]     since  [cos²(6θ) + sin²(6θ)] = 1

6 0
3 years ago
A satellite is 19,000 miles from the horizon of Earth. Earth’s radius is about 4,000 miles. Find the approximate distance the sa
Jobisdone [24]

Answer:

The approximate distance is 15416 miles....

Step-by-step explanation:

We have given:

A satellite is 19,000 miles from the horizon of earth.

The radius is 4,000 miles.

Lets say that BC =x

AO = OB = 4,000 miles

AC = 19,000 miles

The tangent from the external point forms right angle with the radius of the circle.

So in ΔABC

(OC)² = (AC)²+(OA)²

where OC = x+4000

AC = 19,000

OA = 4000

Therefore,

(x+4000)² = (19,000)² +(4,000)²

Take square root at both sides:

√(x+4000)²  = √(19,000)² +(4,000)²

x+4000  =√361000000+16000000

x+4000 = √377000000

x+4000 = 19416.48

x= 19416.48 - 4000

x = 15416.48

Therefore the approximate distance is 15416 miles....

6 0
3 years ago
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