Solve the solution of a system of linear equation 1/2 x + y = - 6 6 x + 2 y = 8
1 answer:
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Answer:
a)
X[bar]= 71.8cm
X[bar]= 72cm
b)
M.A.D.= 8.16cm
M.A.D.= 5.4cm
c) The data set for Soil A is more variable.
Step-by-step explanation:
Hello!
The data in the stem-and-leaf plots show the heights in cm of Teddy Bear sunflowers grown in two different types of soil (A and B)
To read the data shown in the plots, remember that the first digit of the number is shown in the stem and the second digit is placed in the leaves.
The two data sets, in this case, are arranged in a "back to back" stem plot, which allows you to compare both distributions. In this type of graph, there is one single stem in the middle, shared by both samples, and the leaves are placed to its left and right of it corresponds to the observations of each one of them.
Since the stem is shared by both samples, there can be observations made only in one of the samples. For example in the first row, the stem value is 5, for the "Soil A" sample there is no leaf, this means that there was no plant of 50 ≤ X < 60 but for "Soil B" there was one observation of 59 cm.
X represents the variable of interest, as said before, the height of the Teddy Bear sunflowers.
a) To calculate the average or mean of a data set you have to add all observations of the sample and divide it by the number of observations:
X[bar]= ∑X/n
For soil A
Observations:
61, 61, 62, 65, 70, 71, 75, 81, 82, 90
The total of observations is n= 10
∑X= 61 + 61 + 62 + 65 + 70 + 71 + 75 + 81 + 82 + 90= 718
X[bar]= ∑X
/n
= 218/10= 71.8cm
For Soil B
Observations:
59, 63, 69, 70, 72, 73, 76, 77, 78, 83
The total of observations is n= 10
∑X= 59 + 63 + 69 + 70 + 72 + 73 + 76 + 77 + 78 + 83= 720
X[bar]= ∑X
/n
= 720/10= 72cm
b) The mean absolute deviation is the average of the absolute deviations of the sample. It is a summary of the sample's dispersion, meaning the greater its value, the greater the sample dispersion.
To calculate the mean absolute dispersion you have to:
1) Find the mean of the sample (done in the previous item)
2) Calculate the absolute difference of each observation and the sample mean |X-X[bar]|
3) Add all absolute differences
4) Divide the summation by the number of observations (sample size,n)
For Soil A
1) X[bar]= 71.8cm
2) Absolute differences |X-X[bar]
|
|61-71.8|= 10.8
|61-71.8|= 10.8
|62-71.8|= 9.8
|65-71.8|= 6.8
|70-71.8|= 1.8
|71-71.8|= 0.8
|75-71.8|= 3.2
|81-71.8|= 9.2
|82-71.8|= 10.2
|90-71.8|= 18.2
3) Summation of all absolute differences
∑|X-X[bar]
|= 10.8 + 10.8 + 9.8 + 6.8 + 1.8 + 0.8 + 3.2 + 9.2 + 10.2 + 18.2= 81.6
4) M.A.D.=∑|X
-X[bar]
|/n
= 81.6/10= 8.16cm
For Soil B
1) X[bar]= 72cm
2) Absolute differences |X-X[bar]
|
|59-72|= 13
|63-72|= 9
|69-72|= 3
|70-72|= 2
|72-72|= 0
|73-72|= 1
|76-72|= 4
|77-72|= 5
|78-72|= 6
|83-72|= 11
3) Summation of all absolute differences
∑ |X-X[bar]
|= 13 + 9 + 3 + 2 + 0 + 1 + 4 + 5 + 6 + 11= 54
4) M.A.D.=∑ |X
-X[bar]
|/n
= 54/10= 5.4cm
c)
If you compare both calculated mean absolute deviations, you can see M.A.D. > M.A.D.
. As said before, the M.A.D. summary of the sample's dispersion. The greater value obtained for "Soil A" indicates this sample has greater variability.
I hope this helps!
Answer:
Step-by-step explanation:
Given:
Type of Flowers = 5
To choose = 4
Required
Number of ways 4 can be chosen
The first flower can be chosen in 5 ways
The second flower can be chosen in 4 ways
The third flower can be chosen in 3 ways
The fourth flower can be chosen in 2 ways
Total Number of Selection = 5 * 4 * 3 * 2
Total Number of Selection = 120 ways;
Alternatively, this can be solved using concept of Permutation;
Given that 4 flowers to be chosen from 5,
then n = 5 and r = 4
Such that
Substitute 5 for n and 4 for r
Hence, the number of ways the florist can chose 4 flowers from 5 is 120 ways
Question:
Which scenario best matches the linear relationship expressed in the equation y = –14x + 1,700?
1) Kent has $1,700 in his bank account and spends $14 each week.
2) Kent has $1,700 in his bank account and deposits $14 each week.
3) Kent had $1,700 in his bank account and deposited another $14.
4) Kent has $14 in his bank account and spent $1,700.
Answer:
Option 1) Kent has $1,700 in his bank account and spends $14 each week.
Step-by-step explanation:
Let x denote the number of weeks.
Option 1: Kent has $1,700 in his bank account and -14x as the negative sign denotes how much amount he spend each week.
Thus, Option 1 is the correct answer.
Option 2: Kent has $1,700 in his bank account and deposits $14 each week.
Writing it as equation, we have, which is not the expressed linear equation.
Hence, Option 2 is not the correct answer.
Option 3: Kent had $1,700 in his bank account and deposited another $14.
Writing it as equation, we have, which is not the expressed linear equation.
Hence, Option 3 is not the correct answer.
Option 4: Kent has $14 in his bank account and spent $1,700.
Writing it as equation, we have, which is not the expressed linear equation.
Hence, Option 4 is not the correct answer.
Thus, the scenario that matches the linear equation relationship expressed in the equation is Option 1.
The answer is Kent has $1,700 in his bank account and spends $14 each week.