It's D, $49.00/wk for x weeks is 49x, plus $18.00 bonus is 49x+18, add the fact that Mini worked for y weeks, 49y.
Read it slowly and out loud till you get it.
None. <span>±</span>
, <span>where </span><span>
p</span><span> is a </span>factor<span> of the </span>constant<span> and </span><span>
q</span><span> is a </span>factor<span> of the leading </span>coefficient<span>.</span>
Here is the solution of the given problem above.
Firstly, to make the solution easier, let us convert the mixed fractions.
2 3/4 is 11/4 (Pounds of beef needed)
1 1/6 is 7/6 (Pounds of beef available)
So, to get how much more he needs, we will deduct 7/6 from 11/4 and we get 19/12. And this fraction is equivalent to option A. 1 7/12. Therefore, he needs 1 7/12 pounds more. hope this answer helps.
Assuming that the order of selection is not important, this is a question of number of ways. In other words, the combination should be computed. That is,
Number of ways of selection 5 flowers = 12C5 = 12!/{5!*(12-5)!} = 12!/{5!*7!} = 792
Therefore, there are 792 ways in which 5 flowers can be selected from the available 12 flowers.
Answer:
Two possible lengths for the legs A and B are:
B = 1cm
A = 14.97cm
Or:
B = 9cm
A = 12cm
Step-by-step explanation:
For a triangle rectangle, Pythagorean's theorem says that the sum of the squares of the cathetus is equal to the hypotenuse squared.
Then if the two legs of the triangle are A and B, and the hypotenuse is H, we have:
A^2 + B^2 = H^2
If we know that H = 15cm, then:
A^2 + B^2 = (15cm)^2
Now, let's isolate one of the legs:
A = √( (15cm)^2 - B^2)
Now we can just input different values of B there, and then solve the value for the other leg.
Then if we have:
B = 1cm
A = √( (15cm)^2 - (1cm)^2) = 14.97
Then we could have:
B = 1cm
A = 14.97cm
Now let's try with another value of B:
if B = 9cm, then:
A = √( (15cm)^2 - (9cm)^2) = 12 cm
Then we could have:
B = 9cm
A = 12cm
So we just found two possible lengths for the two legs of the triangle.
