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2 years ago

The element that corresponds to the electron configuration 1s22s22p63s23p64s13d5 is

Chemistry

1 answer:

vampirchik [111]2 years ago

5 0

Answer:

It's Chromium , I guess

Explanation:

chromium and Copper is some kind of special in

the complete electronic structure of an element

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How many milliliters of 0.128 M nitric acid are required to neutralize 11.1 mL of 0.184 M sodium hydroxide? Answer with the corr

Llana [10]

Answer:

I think 7.72 mL

11.1/184 × 128/184=7.72

4 0

2 years ago

Bas + PtF2 → BaF2 + Pts Need to balance it

Basile [38]

it is already balanced

REACTANTS

Barium sulfide (BaS) + platinum (Ii) fluoride

PRODUCT

Barium fluoride (BaF2) + Cooperite (PtS)

Hope this answer helps you dear! take care

5 0

2 years ago

Calculate the wavelength of a photon of light having a frequency of 3.50 x 1015 Hz.

Aliun [14]

Answer:

Wavelength, $\lambda=8.57\times 10^{-8}\ m$

Explanation:

Given that,

Frequency, $f=3.5\times 10^{15}\ Hz$

We need to find the wavelength of a photon of light. The relation between frequency and wavelength is as follows :

$c=f\lambda\\\\\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{3.5\times 10^{15}}\\\\\lambda=8.57\times 10^{-8}\ m$

So, the wavelength of the light is $8.57\times 10^{-8}\ m$ .

4 0

2 years ago

Please help me will mark brainliest

LuckyWell [14K]

Answer:

accretion

Explanation:

the coming together and cohesion of matter under the influence of gravitation to form larger bodies.

8 0

2 years ago

The equilibrium constant, Kc, for the following reaction is 5.10×10-6 at 548 K. NH4Cl(s) NH3(g) + HCl(g) Calculate the equilibri

levacccp [35]

Answer: The equilibrium concentration of HCl is $2.26\times 10^{-3}M$

Explanation:

We are given:

Moles of $NH_4Cl(s)$ = 0.564 moles

Volume of vessel = 1.00 L

Molarity is calculated by using the equation:

$\text{Molarity}=\frac{\text{Number of moles}}{\text{Volume of solution (in L)}}$

Molarity of $NH_4Cl=\frac{0.564}{1}=0.564M$

The given chemical equation follows:

$NH_4Cl(s)\rightleftharpoons NH_3(g)+HCl(g)$

Initial: 0.564

At eqllm: 0.564-x x x

The expression of $K_c$ for above equation follows:

$K_c=[NH_3][HCl]$

The concentration of pure solid and pure liquid is taken as 1.

We are given:

$K_c=5.10\times 10^{-6}$

Putting values in above equation, we get:

$5.10\times 10^{-6}=x\times x\\\\x=2.26\times 10^{-3}M,-2.26\times 10^{-3}M$

Negative sign is neglected because concentration cannot be negative.

So, $[HCl]=2.26\times 10^{-3}M$

Hence, the equilibrium concentration of HCl is $2.26\times 10^{-3}M$

5 0

3 years ago