All categories

3 years ago

I need help ASAP!!! What type of chemical bond holds Lit and F together in LiF?

Chemistry

1 answer:

Bond [772]3 years ago

4 0

Answer:

The correct answer is a) lonic Bond

Explanation:

Lithium fluoride (LiF) is a salt, formed by an ionic bond between a metal (Li) compound and a nonmetal (F).

You might be interested in

0.47 M KNO3 solution contains .757475 mol of KNO3 what is the volume

vfiekz [6]

Answer:

Volume is the quantity of three-dimensional

Explanation:

7 0

2 years ago

PLEASE HELPPP!!!!!!!!!!!!!!!!!!!!

riadik2000 [5.3K]

Similarities. very useful
differences. coal is a pullutant. while womd is not. i guess

6 0

3 years ago

Read 2 more answers

In a thin layer chromatography experiment, a plate of length 9.3 cm was used and a horizontal line was made at 1.45 cm above the

dezoksy [38]

Answer: The $R_f$ value is 0.664

Explanation:

Distance travelled by solvent front = (7.7-1.45)cm = 6.25 cm

Distance travelled by unknown = (5.6-1.45) cm = 4.15 cm

The retention factor or the $R_f$ value is defined as the ratio of distance traveled by the unknown to the distance traveled by the solvent front.

$R_f=\frac{\text {distance travelled by unknown}}{\text {distance travelled by solvent}}$

$R_f=\frac{4.15}{6.25}=0.664$

Thus the $R_f$ value is 0.664

6 0

2 years ago

For a laboratory investigation some students put a strip of shiny metal into a beaker of blue solution and then stored the beake

KatRina [158]

Answer:

Explanation:

8 0

2 years ago

What compound is formed when methyloxirane (1,2-epoxypropane) is reacted with ethylmagnesium bromide followed by treatment with

Pavlova-9 [17]

Answer:

Pentan-2-ol

Explanation:

On this reaction, we have a Grignard reagent (ethylmagnesium bromide), therefore we will have the production of a carbanion (step 1). Then this carbanion can attack the least substituted carbon in the epoxide in this case carbon 1 (step 2). In this step, the epoxide is open and a negative charge is generated in the oxygen. The next step, is the treatment with aqueous acid, when we add acid the hydronium ion ( $H^+$ ) would be produced, so in the reaction mechanism, we can put the hydronium ion. This ion would be attacked by the negative charge produced in the second step to produce the final molecule: "Pentan-2-ol".

See figure 1

I hope it helps!

5 0

3 years ago